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ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
What does "" mean in logic?
 one year ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
divides
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
The division thing? Yes.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
Except for 0.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
What if \(\rm n = 0\)?
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
n^2=n*n so (n*n)/n=n
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Truesomeness
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
Though the statement is true for \(\mathbb{Z}^+\)
 one year ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
Dont read :\[n\mid n^2\]as division. By definition, \[a\mid b \iff b=ak ,k\in \mathbb{Z}\]there is no division taking place. By this definition, 0 does divide 0^2 since 0^2=0*0
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
I've always heard, zero cannot divide anything.
 one year ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
You are thinking of fractions. Notice the definition doesnt contain anything about fractions.
 one year ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
its a statement only about multiplication.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[ab \iff \exists q[b=aq],a\neq 0\]
 one year ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
ah, then i am mistaken. if a cant be zero then what i posted is wrong.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
So, in fact, we do have fractions in the definition.
 one year ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
hmmm, i still wouldnt say there are fractions. This is generally the way they talk about division in Rings, where only multiplication and addition are defined. But yes, a cannot be zero. http://primes.utm.edu/glossary/xpage/divides.html
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\(ab\) denotes \(b\) is divisible by \( a \)
 one year ago
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