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ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
What does "" mean in logic?
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
divides
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
The division thing? Yes.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
Except for 0.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
What if \(\rm n = 0\)?
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
n^2=n*n so (n*n)/n=n
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Truesomeness
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
Though the statement is true for \(\mathbb{Z}^+\)
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
Dont read :\[n\mid n^2\]as division. By definition, \[a\mid b \iff b=ak ,k\in \mathbb{Z}\]there is no division taking place. By this definition, 0 does divide 0^2 since 0^2=0*0
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
I've always heard, zero cannot divide anything.
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
You are thinking of fractions. Notice the definition doesnt contain anything about fractions.
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
its a statement only about multiplication.
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[ab \iff \exists q[b=aq],a\neq 0\]
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
ah, then i am mistaken. if a cant be zero then what i posted is wrong.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.2
So, in fact, we do have fractions in the definition.
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
hmmm, i still wouldnt say there are fractions. This is generally the way they talk about division in Rings, where only multiplication and addition are defined. But yes, a cannot be zero. http://primes.utm.edu/glossary/xpage/divides.html
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\(ab\) denotes \(b\) is divisible by \( a \)
 2 years ago
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