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anonymous
 3 years ago
find (f^1)'(a)
f(x)=sqrt(x^3+x^2+x+1) a=2
anonymous
 3 years ago
find (f^1)'(a) f(x)=sqrt(x^3+x^2+x+1) a=2

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the inverse of sqrt(x^3+y^2+x+1)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i believe you're t(rying to find derivative of that equation then *2? so (x^3 + x^2 + 1)^1/2 1/2(x^3+x^2+1)^1/2 * (3x+2x) via chain rule rest just simply and afterwards multiple by a=2 to complete answer
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