## coolaidd Group Title .. one year ago one year ago

1. ParthKohli Group Title

Just subtract for finding (f - g) and add for finding (f + g).

2. tjones89 Group Title

(f-g)(x) = f(x) - g(x)

3. ParthKohli Group Title

$\rm (f - g)(x) = (2x - 2)-(x + 4)$$\rm (f + g)(x) = (2x + 2) + (x + 4)$

4. ParthKohli Group Title

Oh, then it gets a little difficult... you have to plug g(x) into f(x).

5. ParthKohli Group Title

For example, if you got $$\rm f(x) = x^2$$ and $$\rm g(x) = x+1$$, then$\rm f(g(x)) = f(x + 1) = (x + 1)^2$

6. coolaidd Group Title

oh..ok :/

7. coolaidd Group Title

soo what would this be?

8. bluebrandon Group Title

for f(g(x)) just replace all the x in 2x-2 with (x+4) and for g(f(x)) just replace all the x in x+4 with (2x-2)

9. jiteshmeghwal9 Group Title

$$x(f-g)$$=$$f(x)-g(x)$$ now put the values of $$f(x)$$ & $$g(x)$$ & solve them.

10. nubeer Group Title

yup.. thats how its done.

11. coolaidd Group Title

thanks!

12. nubeer Group Title

welcome.

13. coolaidd Group Title

so would it then be 2x+8-2 8x-8?

14. nubeer Group Title

how u got 8x-8?

15. coolaidd Group Title

2x times +4 and-2 times +4

16. nubeer Group Title

noooo... (2x-2) +4 u have to just open the bracket.. if there is a positive or negative sign outside the bracket that means its addint or subtracting not multiplying. your expression will be like 2x-2 +4

17. coolaidd Group Title

so it would just be 2x-2 +4? i dont have to solve it?

18. nubeer Group Title

(2x-2)4 if it was written liek this then u had to multiplied.. and yes that would be your answer just simplify it 2x+2 would be your answer for gf(x)

19. coolaidd Group Title

thanks!

20. nubeer Group Title

welcome ..