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anonymous
 3 years ago
integrate by parts: ∫arctan4tdt
anonymous
 3 years ago
integrate by parts: ∫arctan4tdt

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TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0\[u=\tan^{1}(4t)\]\[dv=tdt\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think you saw an extra t in there dv should just be dt

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0\[u=\tan^{1}(4t)\]\[dv=dt\]I'm tired now, g'night!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[du = \frac{ 4 }{ 1+t^2 }dt\] \[v = t\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[I = t*\arctan(4t)  4\int\limits_{}^{}\frac{ t }{ 1+t^2 }dt\] usub from here should do it

Fellowroot
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350628982821:dw
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