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eexiam Group Title

integrate by parts: ∫arctan4tdt

  • 2 years ago
  • 2 years ago

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  1. TuringTest Group Title
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    \[u=\tan^{-1}(4t)\]\[dv=tdt\]

    • 2 years ago
  2. tjones89 Group Title
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    i think you saw an extra t in there dv should just be dt

    • 2 years ago
  3. TuringTest Group Title
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    yes I did :)

    • 2 years ago
  4. TuringTest Group Title
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    \[u=\tan^{-1}(4t)\]\[dv=dt\]I'm tired now, g'night!

    • 2 years ago
  5. tjones89 Group Title
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    \[du = \frac{ 4 }{ 1+t^2 }dt\] \[v = t\]

    • 2 years ago
  6. tjones89 Group Title
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    \[I = t*\arctan(4t) - 4\int\limits_{}^{}\frac{ t }{ 1+t^2 }dt\] u-sub from here should do it

    • 2 years ago
  7. Fellowroot Group Title
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    |dw:1350628982821:dw|

    • 2 years ago
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