Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Jonask Group Title

if

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. estudier Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    IF you can keep your head when all about you. Are losing theirs and blaming it on you, If you can trust yourself when all men doubt you, But make ...

    • 2 years ago
  2. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[a,b,c \]are roots of the equation\[x^3-x-1=0\] compute \[\frac{ 1-a }{ 1+a }+\frac{ 1-b }{ 1+b }+\frac{ 1-c }{ 1+c}\]

    • 2 years ago
  3. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    simplified \[\frac{ 1 }{ a+1 }+\frac{ 1 }{ b+1 }+\frac{ 1 }{ c+1 }-3\] note\[a^3=a+1,b^3=b+1,c^3=c+1\]

    • 2 years ago
  4. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so\[\frac{ 1 }{ a^3 }+\frac{ 1 }{ b^3 }+\frac{ 1 }{ c^3 }-3\]

    • 2 years ago
  5. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    if we divide by a,b,c\[1-\frac{ 1 }{ a^2 }=\frac{ 1 }{ a^3 }\]

    • 2 years ago
  6. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[[3-(\frac{ 1 }{ a^2 }+\frac{ 1 }{ b^2 }+\frac{ 1 }{ c^2 })]-3\]

    • 2 years ago
  7. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[(x-a)(x-b)(x-c)=x^3-x^2(a+b+c)+x(bc+ab+ac)-(abc)\] coefeecients of x^2 is 0 x is -1 and constant 0 so\[a+b+c=0,bc+ab+ac=-1,abc=1\]

    • 2 years ago
  8. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\frac{ (ac)^2+(bc)^2+(ab)^2}{ (abc)^2 }\] we need to get this with all the info

    • 2 years ago
  9. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[(x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx)\]

    • 2 years ago
  10. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[(0)^2=(ab)^2+(bc)^2+(ca)^2+2(-1)\] \[(ab)^2+(bc)^2+(ca)^2=2\]

    • 2 years ago
  11. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so the answer to\[[3-(\frac{ (ab)^2(bc)^2+(ca))^2 }{ (abc)^2 })]-3=[3-\frac{ 2 }{ 1 }]-3=-2\]

    • 2 years ago
  12. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    wat doyou think guys,please help

    • 2 years ago
  13. Zekarias Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Actually the answer is 1 So you are not correct

    • 2 years ago
  14. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    how can we find the answer 1

    • 2 years ago
  15. Zekarias Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\frac{ 1-a }{ 1+a }+\frac{ 1-b }{ 1+b }+\frac{ 1-c }{ 1+c }\] \[-1+\frac{ 2 }{ 1+a }-1+\frac{ 2 }{ 1+b }-1+\frac{ 2 }{ 1+c }\] \[2(\frac{ 1 }{ 1+a }+\frac{ 1 }{ 1+b }+\frac{ 1 }{ 1+c })-3\] \[2(\frac{ (1+b)(1+c)+(1+a)(1+c)+(1+a)(1+b) }{ (1+a)(1+b)(1+c) })-3\] \[2(\frac{ (ab+ac+bc)+2(a+b+c)+3 }{ abc+(ab+ac+bc)+(a+b+c)+1 })-3\]Now insert the respective values so as to get the ANSWER 1

    • 2 years ago
  16. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i am out of medals...thanks

    • 2 years ago
  17. estudier Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Multiply it out directly: -> 3 + (a + b + c) - (ab +bc + ca) - 3abc / (a+1)(b+1)(c+1) -> 3 + (a + b + c) - (ab +bc + ca) - 3abc / a^3b^3c^3 = 3 +1 - 3 /1 = 1

    • 2 years ago
  18. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i really went for miles to show a centimeter journey

    • 2 years ago
  19. estudier Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Now and again, it is just a question of doing the first thing that comes to mind....:-)

    • 2 years ago
  20. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[x^3−x−1=0\] 1 is not a solution as \[1^3−1−1=1\neq0\]

    • 2 years ago
  21. estudier Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    We are not finding solutions, we are evaluating the expression in the top post...

    • 2 years ago
  22. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    to hard for me

    • 2 years ago
  23. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    is it possible to getthe values ofa,b,c

    • 2 years ago
  24. estudier Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Do you mean by hand?

    • 2 years ago
  25. estudier Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    http://en.wikipedia.org/wiki/Plastic_number

    • 2 years ago
  26. Jonask Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    very helpful,i asked this becuause 1 was looking for the solution of the cube

    • 2 years ago
  27. estudier Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    http://en.wikipedia.org/wiki/Cubic_function#Reduction_to_a_depressed_cubic

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.