Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

A 20kg body is connected to a rope of breaking strength 40 kgwt. If it is moved down with a speed of 9.5m/s at certain instant. The shortest distance in which it can be stopped is (4m, 0.25m, 1 m or 1.25 m)

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

Speed is 4.9 m/s . My mistake.
try to find acceleration using F=ma ... probably F=40 and m=20 then use this formula v^2 = u^2 + 2 a s u=0, v=4.9, use 'a' from above ... find 's' which is distance.
a =40/20=2 m/s^2. hence S = 4.9 x4.9 /2x2 =6.0025 .but options are 4,0.25,1 &1.25. How to go about it?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

what does "breaking strength 40 kgwt" mean??
I am not very sure .I am trying help my daughter in her homework. As I understand it should the maximum force which that rope can withstand.Will there be force due to gravity play its part?
I am not sure ... since no details have given.
is the length of wire given?
No .I have posted the question verbatim from her question paper.
try putting F = 40*9.8
Then a = 40x9.8/20 =19.6 m/sec^2 & S = 4.9 x4.9/2x 19.6=0.6125. But it is not near to any of the four options given.
the problem is with "40 kgwt." I can't decipher what it means ... this is 11th grade Q right?
Yeah it is class 11 std in India. My daughter is going through a recap as she is to sit for a National level exam for admission to med college.
If we take initial vel as 4.9 m/s and allow force of gravity then v^2 =4.9^2 +2x 9.8x S or Shortest dist =( v^2 -9.8^2)/9.8x2 but we do not know the value of V final. Can there be some other way?
try opposite, using those distances, find acceleration (4m, 0.25m, 1 m or 1.25 m) calculate force and see how this relates to 40kgwt
Ok i shall do that. but got to leave now . Shall catch up .Thanks.

Not the answer you are looking for?

Search for more explanations.

Ask your own question