A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.1One is i=2 and j=5

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.2\[j^3(i^2)^3=61\] \[(ji^2)(j^2+ij+i^2)=61\] 61 is prime so 61(1) are the only factors hence \[ji^2=1,j^2+ij+i^2=61\]

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.1Looks like 4 solution.

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.2but we imgore the fact that it can be vise versa 1(61)

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1350668697206:dw

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.2oh thanks i see my folly i did not factor 2

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=All+integer+solution+x^3+%3D+61+%2B+y^6

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.1Looks like 2 and 5 only.......... But how to prove it mathematically.

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.2\[i^4+2i^2+1+i^2(1+i^2)+i^4=61\] \[3i^4+3i^260=0,i^4+i^210=0\]

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.2\[i=\pm 2,j=(\pm2)^2+1=5\]

Zekarias
 2 years ago
Best ResponseYou've already chosen the best response.0@Jonask you are very correct
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.