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hejå
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little confused with this one (c)Calculate the mass of iron metal (in grams) that can be prepared from 150 grams of aluminum and 250 grams of iron(III) oxide
 one year ago
 one year ago
hejå Group Title
little confused with this one (c)Calculate the mass of iron metal (in grams) that can be prepared from 150 grams of aluminum and 250 grams of iron(III) oxide
 one year ago
 one year ago

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dawn_pingpong Group TitleBest ResponseYou've already chosen the best response.0
Its a redox reaction: Basically the reaction is as follows: \[2Al + Fe_{2}O_{3} \rightarrow Al _{2}O _{3}+2Fe\] There are \[150\div27.0=5.5556\] moles of Aluminium,and \[250\div(56\times2+16\times3)=1.5625\] moles of iron (III) oxide. Which material is the limiting reagent? Very obviously, iron oxide is the limiting reagent, as there is less of that material. Thus, the mass of iron that can be prepared will be the amount of iron in 1.5625 mol of iron (III) oxide. I think you will be able to figure that out:)
 one year ago

hejå Group TitleBest ResponseYou've already chosen the best response.0
i have it as 87.25781250009746 but that is wrong :s
 one year ago

dawn_pingpong Group TitleBest ResponseYou've already chosen the best response.0
Oh sorry I realised where the problem is coming from and apparently we're not supposed to post full solutions so I deleted it:P Sorry!
 one year ago
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