A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
little confused with this one (c)Calculate the mass of iron metal (in grams) that can be prepared from 150 grams of aluminum and 250 grams of iron(III) oxide
 2 years ago
little confused with this one (c)Calculate the mass of iron metal (in grams) that can be prepared from 150 grams of aluminum and 250 grams of iron(III) oxide

This Question is Closed

dawn_pingpong
 2 years ago
Best ResponseYou've already chosen the best response.0Its a redox reaction: Basically the reaction is as follows: \[2Al + Fe_{2}O_{3} \rightarrow Al _{2}O _{3}+2Fe\] There are \[150\div27.0=5.5556\] moles of Aluminium,and \[250\div(56\times2+16\times3)=1.5625\] moles of iron (III) oxide. Which material is the limiting reagent? Very obviously, iron oxide is the limiting reagent, as there is less of that material. Thus, the mass of iron that can be prepared will be the amount of iron in 1.5625 mol of iron (III) oxide. I think you will be able to figure that out:)

hejå
 2 years ago
Best ResponseYou've already chosen the best response.0i have it as 87.25781250009746 but that is wrong :s

dawn_pingpong
 2 years ago
Best ResponseYou've already chosen the best response.0Oh sorry I realised where the problem is coming from and apparently we're not supposed to post full solutions so I deleted it:P Sorry!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.