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Multiply the equation by the LCD.

Sorry I should have stated to solve the equation for x.

K, let's start again.....

okay

What is it u want to do?

|dw:1350674953315:dw|

Yes, so what is it u want to do?

Multiply (-1), (2x/x+3), and (-2x/x+2) by the LCD of (x+3) and (x+2).

yes

LCD of (x+3) and (x+2) is just (x+3)(x+2)
I will leave you to it, it is not too hard to do.

Okay. Thank you. I know the answer is (-1,0). I just wanted to make sure I was on the right path.

U should also note that x=-3 and x = -2 are not defined for this equation.

correct

Could you please explain the shorter way of doing this type of equation.

Wow that is much quicker! Thank you so much

yw:)

Could I use this shorter way for this equation as well? (see drawing)

|dw:1350677688912:dw|

Yes, u can.

Thanks. When I add the terms on the LHS I get (z+1) / (z-6). Is this correct?

No, (z+1) + 1*(z-6) / (z-6) = (2z-5) / (z-6)

Gotcha. Thanks