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LilVeroDez13
 3 years ago
Select the counterexample that makes this conjecture false:
For any real number x, x2 ≥ x.
LilVeroDez13
 3 years ago
Select the counterexample that makes this conjecture false: For any real number x, x2 ≥ x.

This Question is Closed

LilVeroDez13
 3 years ago
Best ResponseYou've already chosen the best response.0x = 1/2 x = 2 x = 3 x = 0

xartaan
 3 years ago
Best ResponseYou've already chosen the best response.1Try plugging in each of those into the equation. And see which one the inequality isn't true for.

LilVeroDez13
 3 years ago
Best ResponseYou've already chosen the best response.0can u help? i forget how to solve inequalitys

xartaan
 3 years ago
Best ResponseYou've already chosen the best response.1Well, you don't need to do much with the inequality other than realize what it is saying which is: given any x, x^2 is always "Greater Than or Equal To" x. So, by testing each choice, i.e. squaring each one, you will find that only one of them gets smaller when squared.

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0There is nothing to solve; it's plugandchug.

xartaan
 3 years ago
Best ResponseYou've already chosen the best response.1The statement is basically saying, "x squared is always bigger than x." You prove this is false by finding a counterexample. In this case, a counterexample is a value for x which when squared, is smaller than just x. Just start squaring things, you'll find the answer!

LilVeroDez13
 3 years ago
Best ResponseYou've already chosen the best response.0i get x = 1/2 :) is that right?
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