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LilVeroDez13
Group Title
Select the counterexample that makes this conjecture false:
For any real number x, x2 ≥ x.
 2 years ago
 2 years ago
LilVeroDez13 Group Title
Select the counterexample that makes this conjecture false: For any real number x, x2 ≥ x.
 2 years ago
 2 years ago

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LilVeroDez13 Group TitleBest ResponseYou've already chosen the best response.0
x = 1/2 x = 2 x = 3 x = 0
 2 years ago

xartaan Group TitleBest ResponseYou've already chosen the best response.1
Try plugging in each of those into the equation. And see which one the inequality isn't true for.
 2 years ago

LilVeroDez13 Group TitleBest ResponseYou've already chosen the best response.0
can u help? i forget how to solve inequalitys
 2 years ago

xartaan Group TitleBest ResponseYou've already chosen the best response.1
Well, you don't need to do much with the inequality other than realize what it is saying which is: given any x, x^2 is always "Greater Than or Equal To" x. So, by testing each choice, i.e. squaring each one, you will find that only one of them gets smaller when squared.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
There is nothing to solve; it's plugandchug.
 2 years ago

xartaan Group TitleBest ResponseYou've already chosen the best response.1
The statement is basically saying, "x squared is always bigger than x." You prove this is false by finding a counterexample. In this case, a counterexample is a value for x which when squared, is smaller than just x. Just start squaring things, you'll find the answer!
 2 years ago

LilVeroDez13 Group TitleBest ResponseYou've already chosen the best response.0
thanks!!
 2 years ago

xartaan Group TitleBest ResponseYou've already chosen the best response.1
Very welcome!
 2 years ago

LilVeroDez13 Group TitleBest ResponseYou've already chosen the best response.0
i get x = 1/2 :) is that right?
 2 years ago
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