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LilVeroDez13
Group Title
Select the counterexample that makes this conjecture false:
For any real number x, x2 ≥ x.
 one year ago
 one year ago
LilVeroDez13 Group Title
Select the counterexample that makes this conjecture false: For any real number x, x2 ≥ x.
 one year ago
 one year ago

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LilVeroDez13 Group TitleBest ResponseYou've already chosen the best response.0
x = 1/2 x = 2 x = 3 x = 0
 one year ago

xartaan Group TitleBest ResponseYou've already chosen the best response.1
Try plugging in each of those into the equation. And see which one the inequality isn't true for.
 one year ago

LilVeroDez13 Group TitleBest ResponseYou've already chosen the best response.0
can u help? i forget how to solve inequalitys
 one year ago

xartaan Group TitleBest ResponseYou've already chosen the best response.1
Well, you don't need to do much with the inequality other than realize what it is saying which is: given any x, x^2 is always "Greater Than or Equal To" x. So, by testing each choice, i.e. squaring each one, you will find that only one of them gets smaller when squared.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
There is nothing to solve; it's plugandchug.
 one year ago

xartaan Group TitleBest ResponseYou've already chosen the best response.1
The statement is basically saying, "x squared is always bigger than x." You prove this is false by finding a counterexample. In this case, a counterexample is a value for x which when squared, is smaller than just x. Just start squaring things, you'll find the answer!
 one year ago

LilVeroDez13 Group TitleBest ResponseYou've already chosen the best response.0
thanks!!
 one year ago

xartaan Group TitleBest ResponseYou've already chosen the best response.1
Very welcome!
 one year ago

LilVeroDez13 Group TitleBest ResponseYou've already chosen the best response.0
i get x = 1/2 :) is that right?
 one year ago
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