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LilVeroDez13

  • 2 years ago

Select the counterexample that makes this conjecture false: For any real number x, x2 ≥ x.

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  1. LilVeroDez13
    • 2 years ago
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    x = 1/2 x = -2 x = |3| x = 0

  2. xartaan
    • 2 years ago
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    Try plugging in each of those into the equation. And see which one the inequality isn't true for.

  3. LilVeroDez13
    • 2 years ago
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    can u help? i forget how to solve inequalitys

  4. xartaan
    • 2 years ago
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    Well, you don't need to do much with the inequality other than realize what it is saying which is: given any x, x^2 is always "Greater Than or Equal To" x. So, by testing each choice, i.e. squaring each one, you will find that only one of them gets smaller when squared.

  5. CliffSedge
    • 2 years ago
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    There is nothing to solve; it's plug-and-chug.

  6. xartaan
    • 2 years ago
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    The statement is basically saying, "x squared is always bigger than x." You prove this is false by finding a counterexample. In this case, a counterexample is a value for x which when squared, is smaller than just x. Just start squaring things, you'll find the answer!

  7. LilVeroDez13
    • 2 years ago
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    okk

  8. LilVeroDez13
    • 2 years ago
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    thanks!!

  9. xartaan
    • 2 years ago
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    Very welcome!

  10. LilVeroDez13
    • 2 years ago
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    i get x = 1/2 :) is that right?

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