## LilVeroDez13 3 years ago Select the counterexample that makes this conjecture false: For any real number x, x2 ≥ x.

1. LilVeroDez13

x = 1/2 x = -2 x = |3| x = 0

2. xartaan

Try plugging in each of those into the equation. And see which one the inequality isn't true for.

3. LilVeroDez13

can u help? i forget how to solve inequalitys

4. xartaan

Well, you don't need to do much with the inequality other than realize what it is saying which is: given any x, x^2 is always "Greater Than or Equal To" x. So, by testing each choice, i.e. squaring each one, you will find that only one of them gets smaller when squared.

5. CliffSedge

There is nothing to solve; it's plug-and-chug.

6. xartaan

The statement is basically saying, "x squared is always bigger than x." You prove this is false by finding a counterexample. In this case, a counterexample is a value for x which when squared, is smaller than just x. Just start squaring things, you'll find the answer!

7. LilVeroDez13

okk

8. LilVeroDez13

thanks!!

9. xartaan

Very welcome!

10. LilVeroDez13

i get x = 1/2 :) is that right?