anonymous
  • anonymous
Select the counterexample that makes this conjecture false: For any real number x, x2 ≥ x.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
x = 1/2 x = -2 x = |3| x = 0
anonymous
  • anonymous
Try plugging in each of those into the equation. And see which one the inequality isn't true for.
anonymous
  • anonymous
can u help? i forget how to solve inequalitys

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anonymous
  • anonymous
Well, you don't need to do much with the inequality other than realize what it is saying which is: given any x, x^2 is always "Greater Than or Equal To" x. So, by testing each choice, i.e. squaring each one, you will find that only one of them gets smaller when squared.
anonymous
  • anonymous
There is nothing to solve; it's plug-and-chug.
anonymous
  • anonymous
The statement is basically saying, "x squared is always bigger than x." You prove this is false by finding a counterexample. In this case, a counterexample is a value for x which when squared, is smaller than just x. Just start squaring things, you'll find the answer!
anonymous
  • anonymous
okk
anonymous
  • anonymous
thanks!!
anonymous
  • anonymous
Very welcome!
anonymous
  • anonymous
i get x = 1/2 :) is that right?

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