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anonymous
 4 years ago
What is the maximum or minimum value of the function? What is the range?
y = –2x^2 + 32x –12
anonymous
 4 years ago
What is the maximum or minimum value of the function? What is the range? y = –2x^2 + 32x –12

This Question is Closed

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.3find f'(x) and equate it to 0 solve for x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I don't understand that ?

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.3oh  i've assumed you know some calculus

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Would it be like y=2(0)^2+32(0)12 ?

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.3no what you have there is the intercept on yaxis

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.3you need to change it to the vertex form y = –2x^2 + 32x –12 = 2(x^2  16x + 6) = 2( x  8)^2 64 + 6) = 2[(x8)^2  58)] so the x coordinate at maximum = 8 a negative coefficient before x^3 means there is a maximum value

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh , but it says the maximum and range is only 116 . its either 116 or 116 ?

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.3at maximum the function has a value 2*58 = 116

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok , i see that . . .

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.3the range is f(x)<= 116

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0less than or greater than ?

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.3below the graph less or equal to 116

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thats what i thought it was (: . Thank you soo much for helping me ! (;
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