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|dw:1350681532092:dw|

i have these formulas given...
The expressions you posted are specific examples, not formulas.
To answer this question
suppose sin x = 1/5 and 0

yes let me try it on a paper.

a= sqrt 24 -> i can reduce giving me
a=sqrt 4 sqrt 6
a= 2sqrt6

yes, use a's value to find
\[ \cos(x)= \frac{2\sqrt{6}}{5}\]

|dw:1350682709676:dw|

sorry about that, this thing is being slow, this openstudy site

being slow
Yes, sometimes it acts up. Some days are better than others.

the cos x is adjacent over hypotenuse

okay i see the cos =5 now. is 2/5 right?

sin x is opp/hyp= 1/5
cos x is adj/hyp= 2sqrt{6}/5

okay let me try it. i am trying to find it on my paper

okay i got this then

sin 2x = 2 sin 1/5 cos 2sqrt 6 / 5

be careful
x is not 1/5 sin(x) is 1/5
try again.

okay

sin 2x = 2sin 1/5 cos x

thats all im understanding

in other words, replace sin x with 1/5 and replace cos(x) with 2sqrt(6)/5

into the formula you gave me? the...sin(2x)= 2 sin(x) cos(x) ?
what is that equation for also?

okay, thank you

like this:
2(1/5) = 2(1/5)(2sqrt6 / 5) ?

HEYY?! i just realized, did we solve the compute cos theta? was that the 2sqrt6 / 5?

hmmm....okay

will the 2 (1/5) = 2/5? or is that wrong?

i ddont know how to mult. fractions.

Here is the first video on trig
http://www.khanacademy.org/math/trigonometry/v/basic-trigonometry

okay. thank you so much. imma watch a few of these then get back to the homework.