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KBeard

  • 3 years ago

Help solving? 2sin3x-1+0

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  1. IdontknowMath
    • 3 years ago
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    \[(\sin^{-1} (1/2))/3=x\]

  2. apple_pi
    • 3 years ago
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    2 sin (3x) - 1 = 0 ? <- did you mean 2 sin (3x) - 1 = 0 2 sin (3x) = 1 sin (3x) = 1/2 3x = 30, 150, 390 ... degrees so how about: 3x = 180n + (-1)^n * 30 x = 60n + (-1)^n * 10

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