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ChmE
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Do you see that EF + FG = EG

kiannaw13
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im a bit confused

ChmE
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If you had to run the distance of EG you first would have to run for E to F and then from F to G to get there, right. So you just ran EF + FG = EG

ChmE
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So we can use this to get the formula (5x + 15) + 53 = 143

ChmE
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solve for x

kiannaw13
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15?

ChmE
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correct

kiannaw13
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thanks :)