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whats the lim x goes to infinity of 2/square root of x

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Rose if you're not convinced, just plug a large number into your calculator to check! :) if you plug one bajillion in for x, what value do you get for the limit? \[\frac{ 2 }{ \sqrt{bajillion} }\approx \frac{ 2 }{ 999999999 } \approx 0\]

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Other answers:

yeah, but do what zepdrix said only for check, because if you do this in a test for example, it will be wrong because infinity is NOT a number...
it is always 0 ?
no! it will depends on what you are taking the limit, always try to simplify the limit, try to do not have a denominator, in this case we can not simplify so we do this
i am trying to solve this problem where x goes to infinity 2+square root of x/ 2- square root of x
i am getting the answer as 1, is it right?
\[\lim_{x \rightarrow \infty}\frac{2+\sqrt{x}}{2-\sqrt{x}}\]
this one?
the limit is equal to -1
have you already study L'hospital rule ?
can you please explain how you got -1?
ok let me explain
got it?
what did you do with the whole numerator thing? u ended up with X
when x goes to infinity, the other terms with lower power we take them off, and stay only with the higher terms them simply if possible and aply the limit
i will post how i got the numerator
ohh , u mean the limit of 4 and 4 sqrt x = 0?
no this i simply take them out because comparing with infinity they make no difference
oh okay,
when you deal with limits on the infinity you can make this assumptions
but take care...
when you see L'hostpital's Rule this limits will became very easy to solve.... you will see
we have not gotten to that yet.
if you do not mind then, I have one more problem. would you explain that one?
thank you
lim sec x x goes to( -pi/2)^+
let me solve here one moment
it is equal to infinity, i will draw here
is it clear?
yes,viewing it.
see, when we have something divide by a number really really really small them it becomes a really really really large number so the limit tends to the infinity
okay, but how did you get that 10?
it is just a notation for this: 0.00000000000000000000000...00000000000001, then we represent this really small or large number with 10 power
oh ,okay. got it.
that (-pi/2)^+ is the same as (-pi/2)?
ALMOST the same, when we have this + is a little more than pi/2
-pi/2, sorry
so, the asnwer will be the same one right?
no, because if we take 1/0 it is not allowed. But 1/0.00000000001 is allowed
we can not divide by 0, NEVER
yes,that is true.
so you got it?
Thank you soooo much.
yw :)
good night, byee
good, bye

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