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roselin Group Title

whats the lim x goes to infinity of 2/square root of x

  • one year ago
  • one year ago

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  1. JoãoVitorMC Group Title
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    0

    • one year ago
  2. roselin Group Title
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    yes

    • one year ago
  3. zepdrix Group Title
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    Rose if you're not convinced, just plug a large number into your calculator to check! :) if you plug one bajillion in for x, what value do you get for the limit? \[\frac{ 2 }{ \sqrt{bajillion} }\approx \frac{ 2 }{ 999999999 } \approx 0\]

    • one year ago
  4. JoãoVitorMC Group Title
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    yeah, but do what zepdrix said only for check, because if you do this in a test for example, it will be wrong because infinity is NOT a number...

    • one year ago
  5. roselin Group Title
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    okay

    • one year ago
  6. roselin Group Title
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    it is always 0 ?

    • one year ago
  7. JoãoVitorMC Group Title
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    no! it will depends on what you are taking the limit, always try to simplify the limit, try to do not have a denominator, in this case we can not simplify so we do this

    • one year ago
  8. roselin Group Title
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    i am trying to solve this problem where x goes to infinity 2+square root of x/ 2- square root of x

    • one year ago
  9. roselin Group Title
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    i am getting the answer as 1, is it right?

    • one year ago
  10. JoãoVitorMC Group Title
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    \[\lim_{x \rightarrow \infty}\frac{2+\sqrt{x}}{2-\sqrt{x}}\]

    • one year ago
  11. JoãoVitorMC Group Title
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    this one?

    • one year ago
  12. roselin Group Title
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    yes,

    • one year ago
  13. JoãoVitorMC Group Title
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    the limit is equal to -1

    • one year ago
  14. JoãoVitorMC Group Title
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    have you already study L'hospital rule ?

    • one year ago
  15. roselin Group Title
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    can you please explain how you got -1?

    • one year ago
  16. roselin Group Title
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    No,

    • one year ago
  17. JoãoVitorMC Group Title
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    ok let me explain

    • one year ago
  18. JoãoVitorMC Group Title
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    |dw:1350703643878:dw|

    • one year ago
  19. JoãoVitorMC Group Title
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    got it?

    • one year ago
  20. roselin Group Title
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    what did you do with the whole numerator thing? u ended up with X

    • one year ago
  21. JoãoVitorMC Group Title
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    when x goes to infinity, the other terms with lower power we take them off, and stay only with the higher terms them simply if possible and aply the limit

    • one year ago
  22. JoãoVitorMC Group Title
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    i will post how i got the numerator

    • one year ago
  23. roselin Group Title
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    ohh , u mean the limit of 4 and 4 sqrt x = 0?

    • one year ago
  24. JoãoVitorMC Group Title
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    |dw:1350704041192:dw|

    • one year ago
  25. JoãoVitorMC Group Title
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    no this i simply take them out because comparing with infinity they make no difference

    • one year ago
  26. roselin Group Title
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    oh okay,

    • one year ago
  27. JoãoVitorMC Group Title
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    when you deal with limits on the infinity you can make this assumptions

    • one year ago
  28. JoãoVitorMC Group Title
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    but take care...

    • one year ago
  29. JoãoVitorMC Group Title
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    when you see L'hostpital's Rule this limits will became very easy to solve.... you will see

    • one year ago
  30. roselin Group Title
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    we have not gotten to that yet.

    • one year ago
  31. JoãoVitorMC Group Title
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    yeah

    • one year ago
  32. roselin Group Title
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    if you do not mind then, I have one more problem. would you explain that one?

    • one year ago
  33. JoãoVitorMC Group Title
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    sure

    • one year ago
  34. roselin Group Title
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    thank you

    • one year ago
  35. roselin Group Title
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    lim sec x x goes to( -pi/2)^+

    • one year ago
  36. JoãoVitorMC Group Title
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    let me solve here one moment

    • one year ago
  37. roselin Group Title
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    okay

    • one year ago
  38. JoãoVitorMC Group Title
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    it is equal to infinity, i will draw here

    • one year ago
  39. roselin Group Title
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    okay

    • one year ago
  40. JoãoVitorMC Group Title
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    |dw:1350704691784:dw|

    • one year ago
  41. JoãoVitorMC Group Title
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    is it clear?

    • one year ago
  42. roselin Group Title
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    yes,viewing it.

    • one year ago
  43. JoãoVitorMC Group Title
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    see, when we have something divide by a number really really really small them it becomes a really really really large number so the limit tends to the infinity

    • one year ago
  44. roselin Group Title
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    okay, but how did you get that 10?

    • one year ago
  45. JoãoVitorMC Group Title
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    it is just a notation for this: 0.00000000000000000000000...00000000000001, then we represent this really small or large number with 10 power

    • one year ago
  46. roselin Group Title
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    oh ,okay. got it.

    • one year ago
  47. roselin Group Title
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    wait,wait

    • one year ago
  48. roselin Group Title
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    that (-pi/2)^+ is the same as (-pi/2)?

    • one year ago
  49. JoãoVitorMC Group Title
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    ALMOST the same, when we have this + is a little more than pi/2

    • one year ago
  50. JoãoVitorMC Group Title
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    -pi/2, sorry

    • one year ago
  51. roselin Group Title
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    so, the asnwer will be the same one right?

    • one year ago
  52. roselin Group Title
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    *answer

    • one year ago
  53. JoãoVitorMC Group Title
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    no, because if we take 1/0 it is not allowed. But 1/0.00000000001 is allowed

    • one year ago
  54. JoãoVitorMC Group Title
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    we can not divide by 0, NEVER

    • one year ago
  55. roselin Group Title
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    yes,that is true.

    • one year ago
  56. JoãoVitorMC Group Title
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    so you got it?

    • one year ago
  57. roselin Group Title
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    yeah.

    • one year ago
  58. roselin Group Title
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    Thank you soooo much.

    • one year ago
  59. JoãoVitorMC Group Title
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    yw :)

    • one year ago
  60. roselin Group Title
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    good night, byee

    • one year ago
  61. JoãoVitorMC Group Title
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    good, bye

    • one year ago
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