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anonymous
 3 years ago
whats the lim x goes to infinity of 2/square root of x
anonymous
 3 years ago
whats the lim x goes to infinity of 2/square root of x

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zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0Rose if you're not convinced, just plug a large number into your calculator to check! :) if you plug one bajillion in for x, what value do you get for the limit? \[\frac{ 2 }{ \sqrt{bajillion} }\approx \frac{ 2 }{ 999999999 } \approx 0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah, but do what zepdrix said only for check, because if you do this in a test for example, it will be wrong because infinity is NOT a number...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no! it will depends on what you are taking the limit, always try to simplify the limit, try to do not have a denominator, in this case we can not simplify so we do this

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am trying to solve this problem where x goes to infinity 2+square root of x/ 2 square root of x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am getting the answer as 1, is it right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow \infty}\frac{2+\sqrt{x}}{2\sqrt{x}}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the limit is equal to 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0have you already study L'hospital rule ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you please explain how you got 1?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350703643878:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what did you do with the whole numerator thing? u ended up with X

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when x goes to infinity, the other terms with lower power we take them off, and stay only with the higher terms them simply if possible and aply the limit

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i will post how i got the numerator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh , u mean the limit of 4 and 4 sqrt x = 0?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350704041192:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no this i simply take them out because comparing with infinity they make no difference

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when you deal with limits on the infinity you can make this assumptions

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when you see L'hostpital's Rule this limits will became very easy to solve.... you will see

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we have not gotten to that yet.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you do not mind then, I have one more problem. would you explain that one?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lim sec x x goes to( pi/2)^+

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let me solve here one moment

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is equal to infinity, i will draw here

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350704691784:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0see, when we have something divide by a number really really really small them it becomes a really really really large number so the limit tends to the infinity

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, but how did you get that 10?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is just a notation for this: 0.00000000000000000000000...00000000000001, then we represent this really small or large number with 10 power

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that (pi/2)^+ is the same as (pi/2)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ALMOST the same, when we have this + is a little more than pi/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, the asnwer will be the same one right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no, because if we take 1/0 it is not allowed. But 1/0.00000000001 is allowed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we can not divide by 0, NEVER

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you soooo much.
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