anonymous
  • anonymous
whats the lim x goes to infinity of 2/square root of x
Calculus1
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
0
anonymous
  • anonymous
yes
zepdrix
  • zepdrix
Rose if you're not convinced, just plug a large number into your calculator to check! :) if you plug one bajillion in for x, what value do you get for the limit? \[\frac{ 2 }{ \sqrt{bajillion} }\approx \frac{ 2 }{ 999999999 } \approx 0\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yeah, but do what zepdrix said only for check, because if you do this in a test for example, it will be wrong because infinity is NOT a number...
anonymous
  • anonymous
okay
anonymous
  • anonymous
it is always 0 ?
anonymous
  • anonymous
no! it will depends on what you are taking the limit, always try to simplify the limit, try to do not have a denominator, in this case we can not simplify so we do this
anonymous
  • anonymous
i am trying to solve this problem where x goes to infinity 2+square root of x/ 2- square root of x
anonymous
  • anonymous
i am getting the answer as 1, is it right?
anonymous
  • anonymous
\[\lim_{x \rightarrow \infty}\frac{2+\sqrt{x}}{2-\sqrt{x}}\]
anonymous
  • anonymous
this one?
anonymous
  • anonymous
yes,
anonymous
  • anonymous
the limit is equal to -1
anonymous
  • anonymous
have you already study L'hospital rule ?
anonymous
  • anonymous
can you please explain how you got -1?
anonymous
  • anonymous
No,
anonymous
  • anonymous
ok let me explain
anonymous
  • anonymous
|dw:1350703643878:dw|
anonymous
  • anonymous
got it?
anonymous
  • anonymous
what did you do with the whole numerator thing? u ended up with X
anonymous
  • anonymous
when x goes to infinity, the other terms with lower power we take them off, and stay only with the higher terms them simply if possible and aply the limit
anonymous
  • anonymous
i will post how i got the numerator
anonymous
  • anonymous
ohh , u mean the limit of 4 and 4 sqrt x = 0?
anonymous
  • anonymous
|dw:1350704041192:dw|
anonymous
  • anonymous
no this i simply take them out because comparing with infinity they make no difference
anonymous
  • anonymous
oh okay,
anonymous
  • anonymous
when you deal with limits on the infinity you can make this assumptions
anonymous
  • anonymous
but take care...
anonymous
  • anonymous
when you see L'hostpital's Rule this limits will became very easy to solve.... you will see
anonymous
  • anonymous
we have not gotten to that yet.
anonymous
  • anonymous
yeah
anonymous
  • anonymous
if you do not mind then, I have one more problem. would you explain that one?
anonymous
  • anonymous
sure
anonymous
  • anonymous
thank you
anonymous
  • anonymous
lim sec x x goes to( -pi/2)^+
anonymous
  • anonymous
let me solve here one moment
anonymous
  • anonymous
okay
anonymous
  • anonymous
it is equal to infinity, i will draw here
anonymous
  • anonymous
okay
anonymous
  • anonymous
|dw:1350704691784:dw|
anonymous
  • anonymous
is it clear?
anonymous
  • anonymous
yes,viewing it.
anonymous
  • anonymous
see, when we have something divide by a number really really really small them it becomes a really really really large number so the limit tends to the infinity
anonymous
  • anonymous
okay, but how did you get that 10?
anonymous
  • anonymous
it is just a notation for this: 0.00000000000000000000000...00000000000001, then we represent this really small or large number with 10 power
anonymous
  • anonymous
oh ,okay. got it.
anonymous
  • anonymous
wait,wait
anonymous
  • anonymous
that (-pi/2)^+ is the same as (-pi/2)?
anonymous
  • anonymous
ALMOST the same, when we have this + is a little more than pi/2
anonymous
  • anonymous
-pi/2, sorry
anonymous
  • anonymous
so, the asnwer will be the same one right?
anonymous
  • anonymous
*answer
anonymous
  • anonymous
no, because if we take 1/0 it is not allowed. But 1/0.00000000001 is allowed
anonymous
  • anonymous
we can not divide by 0, NEVER
anonymous
  • anonymous
yes,that is true.
anonymous
  • anonymous
so you got it?
anonymous
  • anonymous
yeah.
anonymous
  • anonymous
Thank you soooo much.
anonymous
  • anonymous
yw :)
anonymous
  • anonymous
good night, byee
anonymous
  • anonymous
good, bye

Looking for something else?

Not the answer you are looking for? Search for more explanations.