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bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
factor or use the quadratic
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
I'm telling you to do it lol
 2 years ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
ok well i wouldnt be asking for help if ik what to do
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=factor%28u%5E2%2B2u2%29
 2 years ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.1
DO you know quadratic formula?
 2 years ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
yes but i get confused on where to put my numbers in at
 2 years ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.1
\[\Large u=\frac{b \pm \sqrt{b^{2}4ac}}{2a}\] here b(coeffi. of u)=2 a(coeffi. of u^2)=1 c = 2 substitute.
 2 years ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
ok u=2+squreroot 2*4*1*2 is this right
 2 years ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.1
\[\Large u=\frac{2 \pm \sqrt{2^{2}4(1)(2)}}{2(1)}\]
 2 years ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
ok now idk were to go frm here
 2 years ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
u=2+sqrt2^2+8
 2 years ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
i am sorry this whole thing is very confusing to me
 2 years ago
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