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bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
factor or use the quadratic
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
I'm telling you to do it lol
 one year ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
ok well i wouldnt be asking for help if ik what to do
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=factor%28u%5E2%2B2u2%29
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.1
DO you know quadratic formula?
 one year ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
yes but i get confused on where to put my numbers in at
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.1
\[\Large u=\frac{b \pm \sqrt{b^{2}4ac}}{2a}\] here b(coeffi. of u)=2 a(coeffi. of u^2)=1 c = 2 substitute.
 one year ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
ok u=2+squreroot 2*4*1*2 is this right
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.1
\[\Large u=\frac{2 \pm \sqrt{2^{2}4(1)(2)}}{2(1)}\]
 one year ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
ok now idk were to go frm here
 one year ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
u=2+sqrt2^2+8
 one year ago

artishaalston Group TitleBest ResponseYou've already chosen the best response.0
i am sorry this whole thing is very confusing to me
 one year ago
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