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u^2+2u-2=0 solve

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factor or use the quadratic
I'm telling you to do it lol

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Other answers:

ok well i wouldnt be asking for help if ik what to do
DO you know quadratic formula?
yes but i get confused on where to put my numbers in at
\[\Large u=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\] here b(coeffi. of u)=2 a(coeffi. of u^2)=1 c = -2 substitute.
ok u=-2+-squreroot 2*-4*1*2 is this right
\[\Large u=\frac{-2 \pm \sqrt{2^{2}-4(1)(-2)}}{2(1)}\]
ok now idk were to go frm here
i am sorry this whole thing is very confusing to me

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