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aroub
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sqrt[6]{c^5d} }{ \sqrt[4]{c^3d^3} }\]

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0\[c^{m/n}=\sqrt[n]{c^m}\]

aroub
 2 years ago
Best ResponseYou've already chosen the best response.0 I never actually solved a question using " the laws of exponents" I just convert the final answer.. So, if you could just show me how or the steps of solving it please :)

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ c^{5/6}d^{1/6} }{ c^{3/4}d^{3/4} }\] so we convert any radical to exponent using the rule above

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0The only law that'd help nice would be:\[\large \rm \sqrt[n]{x^m} = x^{m \over n}\]

aroub
 2 years ago
Best ResponseYou've already chosen the best response.0I know that rule! But then what?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Also, you gotta use:\[\rm {a^x \over a^y} = {a^{x  y}}\]and\[\rm {a^x}\cdot {a^y} = a^{x + y}\]

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Then, as JonasK pointed.

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0\[(\frac{ c^{5/6} }{ c^{3/4} })(\frac{ d^{1/6} }{ d^{3/4} })\]

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0can you use the rule by @ParthKohli \[\frac{ a^m }{ a^n }=a^{mn}\]

aroub
 2 years ago
Best ResponseYou've already chosen the best response.0Jonask, just continue solving please :) All I need is the steps!

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0\[c^{5/63/4}d^{1/63/4}\]

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0same base=subtract powers

aroub
 2 years ago
Best ResponseYou've already chosen the best response.0cant you just add the numerator with numerator and the denominator with the denominator?

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0no we can only addif they are both having same base

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0no c and d are not the same variable \[\frac{ c^n*c^m }{ d^nd^m }=\frac{ c^{m+n} }{ d^{m+n} }\]

aroub
 2 years ago
Best ResponseYou've already chosen the best response.0Ahh, that's true! Sorry :]

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0\[c^{2/24}d^{14/12}\] is the answer lets try this one\[\frac{ x^3y^{2} }{ \sqrt[3]{x^2y^2}}\]

jhonyy9
 2 years ago
Best ResponseYou've already chosen the best response.0@aroub sorry for this question ,,so why is this like difficile for you ?

aroub
 2 years ago
Best ResponseYou've already chosen the best response.0No, it's okay! I'll tell you why, right there's two ways of solving this? First you can either solve it by keeping the radicals and then the final answer you can convert it OR by using the laws of exponents.. I always solve it using the first one I find it easier. But then I found it that I have to solve it using the laws of exponents, so here I am >.<

jhonyy9
 2 years ago
Best ResponseYou've already chosen the best response.0,,law of exponents" what method of solving is this ?

aroub
 2 years ago
Best ResponseYou've already chosen the best response.0You convert EVERYTHING to exponents!

jhonyy9
 2 years ago
Best ResponseYou've already chosen the best response.0yes than this mean very very easy

jhonyy9
 2 years ago
Best ResponseYou've already chosen the best response.0begin with sqrtx =x^(1/2)

aroub
 2 years ago
Best ResponseYou've already chosen the best response.0Lol, no to me . Well, I know how to convert them to exponents but then I have nooo ideaa! Anyway, thanks everyoonee! I gtg :D

jhonyy9
 2 years ago
Best ResponseYou've already chosen the best response.0or a^(3/2)  = a^((3/2)(1/3)) a^(1/3) right ?

jhonyy9
 2 years ago
Best ResponseYou've already chosen the best response.0so and i think this will be the law of exponents method sure yes ?

phi
 2 years ago
Best ResponseYou've already chosen the best response.1I assume you have the answer, but to finish this post: \[ C^{(\frac{5}{6}\frac{3}{4})}\cdot D^{(\frac{1}{6}\frac{3}{4})} \] C's exponent is \[ \frac{5}{6}\frac{3}{4} =\frac{5}{6} \cdot \frac{2}{2}\frac{3}{4} \cdot \frac{3}{3}= \frac{10}{12} \frac{9}{12}= \frac{1}{12}\] D's exponent is \[ \frac{1}{6}\frac{3}{4} =\frac{1}{6} \cdot \frac{2}{2}\frac{3}{4} \cdot \frac{3}{3}= \frac{2}{12} \frac{9}{12}= \frac{7}{12}\] you now hve \[ C^{\frac{1}{12}}D^{\frac{7}{12}}= (\frac{C}{D^7})^\frac{1}{12}\] or \[\sqrt[12]{\frac{C}{D^7}}\]

aroub
 2 years ago
Best ResponseYou've already chosen the best response.0That's the answer that I actually wanted! @phi thanks a looooottt ^_^
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