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aroub Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ \sqrt[6]{c^5d} }{ \sqrt[4]{c^3d^3} }\]
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[c^{m/n}=\sqrt[n]{c^m}\]
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
 I never actually solved a question using " the laws of exponents" I just convert the final answer.. So, if you could just show me how or the steps of solving it please :)
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ c^{5/6}d^{1/6} }{ c^{3/4}d^{3/4} }\] so we convert any radical to exponent using the rule above
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
The only law that'd help nice would be:\[\large \rm \sqrt[n]{x^m} = x^{m \over n}\]
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
I know that rule! But then what?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Also, you gotta use:\[\rm {a^x \over a^y} = {a^{x  y}}\]and\[\rm {a^x}\cdot {a^y} = a^{x + y}\]
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Then, as JonasK pointed.
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[(\frac{ c^{5/6} }{ c^{3/4} })(\frac{ d^{1/6} }{ d^{3/4} })\]
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
can you use the rule by @ParthKohli \[\frac{ a^m }{ a^n }=a^{mn}\]
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
Jonask, just continue solving please :) All I need is the steps!
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[c^{5/63/4}d^{1/63/4}\]
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
same base=subtract powers
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
cant you just add the numerator with numerator and the denominator with the denominator?
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
can you illustrate
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
no we can only addif they are both having same base
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
they have the same base
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
no c and d are not the same variable \[\frac{ c^n*c^m }{ d^nd^m }=\frac{ c^{m+n} }{ d^{m+n} }\]
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
Ahh, that's true! Sorry :]
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
so what is our answer
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[c^{2/24}d^{14/12}\] is the answer lets try this one\[\frac{ x^3y^{2} }{ \sqrt[3]{x^2y^2}}\]
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
@aroub sorry for this question ,,so why is this like difficile for you ?
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
No, it's okay! I'll tell you why, right there's two ways of solving this? First you can either solve it by keeping the radicals and then the final answer you can convert it OR by using the laws of exponents.. I always solve it using the first one I find it easier. But then I found it that I have to solve it using the laws of exponents, so here I am >.<
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
,,law of exponents" what method of solving is this ?
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
You convert EVERYTHING to exponents!
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
yes than this mean very very easy
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
begin with sqrtx =x^(1/2)
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
Lol, no to me . Well, I know how to convert them to exponents but then I have nooo ideaa! Anyway, thanks everyoonee! I gtg :D
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
or a^(3/2)  = a^((3/2)(1/3)) a^(1/3) right ?
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
so and i think this will be the law of exponents method sure yes ?
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
ok good luck bye
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
Thanks! Bye =D
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
I assume you have the answer, but to finish this post: \[ C^{(\frac{5}{6}\frac{3}{4})}\cdot D^{(\frac{1}{6}\frac{3}{4})} \] C's exponent is \[ \frac{5}{6}\frac{3}{4} =\frac{5}{6} \cdot \frac{2}{2}\frac{3}{4} \cdot \frac{3}{3}= \frac{10}{12} \frac{9}{12}= \frac{1}{12}\] D's exponent is \[ \frac{1}{6}\frac{3}{4} =\frac{1}{6} \cdot \frac{2}{2}\frac{3}{4} \cdot \frac{3}{3}= \frac{2}{12} \frac{9}{12}= \frac{7}{12}\] you now hve \[ C^{\frac{1}{12}}D^{\frac{7}{12}}= (\frac{C}{D^7})^\frac{1}{12}\] or \[\sqrt[12]{\frac{C}{D^7}}\]
 2 years ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
That's the answer that I actually wanted! @phi thanks a looooottt ^_^
 2 years ago
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