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aroubBest ResponseYou've already chosen the best response.0
\[\frac{ \sqrt[6]{c^5d} }{ \sqrt[4]{c^3d^3} }\]
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
\[c^{m/n}=\sqrt[n]{c^m}\]
 one year ago

aroubBest ResponseYou've already chosen the best response.0
 I never actually solved a question using " the laws of exponents" I just convert the final answer.. So, if you could just show me how or the steps of solving it please :)
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
\[\frac{ c^{5/6}d^{1/6} }{ c^{3/4}d^{3/4} }\] so we convert any radical to exponent using the rule above
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
The only law that'd help nice would be:\[\large \rm \sqrt[n]{x^m} = x^{m \over n}\]
 one year ago

aroubBest ResponseYou've already chosen the best response.0
I know that rule! But then what?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Also, you gotta use:\[\rm {a^x \over a^y} = {a^{x  y}}\]and\[\rm {a^x}\cdot {a^y} = a^{x + y}\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Then, as JonasK pointed.
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
\[(\frac{ c^{5/6} }{ c^{3/4} })(\frac{ d^{1/6} }{ d^{3/4} })\]
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
can you use the rule by @ParthKohli \[\frac{ a^m }{ a^n }=a^{mn}\]
 one year ago

aroubBest ResponseYou've already chosen the best response.0
Jonask, just continue solving please :) All I need is the steps!
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
\[c^{5/63/4}d^{1/63/4}\]
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
same base=subtract powers
 one year ago

aroubBest ResponseYou've already chosen the best response.0
cant you just add the numerator with numerator and the denominator with the denominator?
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
no we can only addif they are both having same base
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
no c and d are not the same variable \[\frac{ c^n*c^m }{ d^nd^m }=\frac{ c^{m+n} }{ d^{m+n} }\]
 one year ago

aroubBest ResponseYou've already chosen the best response.0
Ahh, that's true! Sorry :]
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
\[c^{2/24}d^{14/12}\] is the answer lets try this one\[\frac{ x^3y^{2} }{ \sqrt[3]{x^2y^2}}\]
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.0
@aroub sorry for this question ,,so why is this like difficile for you ?
 one year ago

aroubBest ResponseYou've already chosen the best response.0
No, it's okay! I'll tell you why, right there's two ways of solving this? First you can either solve it by keeping the radicals and then the final answer you can convert it OR by using the laws of exponents.. I always solve it using the first one I find it easier. But then I found it that I have to solve it using the laws of exponents, so here I am >.<
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.0
,,law of exponents" what method of solving is this ?
 one year ago

aroubBest ResponseYou've already chosen the best response.0
You convert EVERYTHING to exponents!
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.0
yes than this mean very very easy
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.0
begin with sqrtx =x^(1/2)
 one year ago

aroubBest ResponseYou've already chosen the best response.0
Lol, no to me . Well, I know how to convert them to exponents but then I have nooo ideaa! Anyway, thanks everyoonee! I gtg :D
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.0
or a^(3/2)  = a^((3/2)(1/3)) a^(1/3) right ?
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.0
so and i think this will be the law of exponents method sure yes ?
 one year ago

phiBest ResponseYou've already chosen the best response.1
I assume you have the answer, but to finish this post: \[ C^{(\frac{5}{6}\frac{3}{4})}\cdot D^{(\frac{1}{6}\frac{3}{4})} \] C's exponent is \[ \frac{5}{6}\frac{3}{4} =\frac{5}{6} \cdot \frac{2}{2}\frac{3}{4} \cdot \frac{3}{3}= \frac{10}{12} \frac{9}{12}= \frac{1}{12}\] D's exponent is \[ \frac{1}{6}\frac{3}{4} =\frac{1}{6} \cdot \frac{2}{2}\frac{3}{4} \cdot \frac{3}{3}= \frac{2}{12} \frac{9}{12}= \frac{7}{12}\] you now hve \[ C^{\frac{1}{12}}D^{\frac{7}{12}}= (\frac{C}{D^7})^\frac{1}{12}\] or \[\sqrt[12]{\frac{C}{D^7}}\]
 one year ago

aroubBest ResponseYou've already chosen the best response.0
That's the answer that I actually wanted! @phi thanks a looooottt ^_^
 one year ago
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