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xcrypt
Group Title
In this page: http://en.wikipedia.org/wiki/Projection_(linear_algebra)#cite_note0
(and in my book)
In linear algebra and functional analysis, a projection is a linear transformation P from a vector space to itself such that P^2 = P
What is the meaning of P^2 here?
 one year ago
 one year ago
xcrypt Group Title
In this page: http://en.wikipedia.org/wiki/Projection_(linear_algebra)#cite_note0 (and in my book) In linear algebra and functional analysis, a projection is a linear transformation P from a vector space to itself such that P^2 = P What is the meaning of P^2 here?
 one year ago
 one year ago

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estudier Group TitleBest ResponseYou've already chosen the best response.1
No sure what u mean, isn't it just as it says at the top of http://en.wikipedia.org/wiki/Projection_(linear_algebra) ie P^2 = P(P(v))
 one year ago

xcrypt Group TitleBest ResponseYou've already chosen the best response.0
I don't mean anything, I'm asking what is meant by it. It might be what you claim, but how is this operation called (at first I thought it was cartesian product or something), and where do you see it at the top?
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.1
Here http://en.wikipedia.org/wiki/Projection_(linear_algebra)#Simple_example
 one year ago

xcrypt Group TitleBest ResponseYou've already chosen the best response.0
I found what is meant by it: http://en.wikipedia.org/wiki/Function_composition
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.1
P(P(v)) IS function composition....:)
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
P is a projection matrix. if you have a vector x Px will give you a vector in some subspace. if x is already in that subspace then you would get x= Px if we sub n Px for x in the equation x=Px we get x= PPx from which we see Px= PPx or P= P^2
 one year ago

xcrypt Group TitleBest ResponseYou've already chosen the best response.0
@ estudier yeah it's a function composition but you didn't tell me what it was called at first :)
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.1
True, you didn't ask for that, though, u asked for the meaning...
 one year ago

xcrypt Group TitleBest ResponseYou've already chosen the best response.0
I did ask for it, but it's no problem really :D
 one year ago
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