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anonymous
 3 years ago
In this page:
http://en.wikipedia.org/wiki/Projection_(linear_algebra)#cite_note0
(and in my book)
In linear algebra and functional analysis, a projection is a linear transformation P from a vector space to itself such that P^2 = P
What is the meaning of P^2 here?
anonymous
 3 years ago
In this page: http://en.wikipedia.org/wiki/Projection_(linear_algebra)#cite_note0 (and in my book) In linear algebra and functional analysis, a projection is a linear transformation P from a vector space to itself such that P^2 = P What is the meaning of P^2 here?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No sure what u mean, isn't it just as it says at the top of http://en.wikipedia.org/wiki/Projection_(linear_algebra) ie P^2 = P(P(v))

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't mean anything, I'm asking what is meant by it. It might be what you claim, but how is this operation called (at first I thought it was cartesian product or something), and where do you see it at the top?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Here http://en.wikipedia.org/wiki/Projection_(linear_algebra)#Simple_example

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I found what is meant by it: http://en.wikipedia.org/wiki/Function_composition

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0P(P(v)) IS function composition....:)

phi
 3 years ago
Best ResponseYou've already chosen the best response.0P is a projection matrix. if you have a vector x Px will give you a vector in some subspace. if x is already in that subspace then you would get x= Px if we sub n Px for x in the equation x=Px we get x= PPx from which we see Px= PPx or P= P^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ estudier yeah it's a function composition but you didn't tell me what it was called at first :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0True, you didn't ask for that, though, u asked for the meaning...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I did ask for it, but it's no problem really :D
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