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apple_pi
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Why is it that when you integrate a function, you get the area under the curve?
 one year ago
 one year ago
apple_pi Group Title
Why is it that when you integrate a function, you get the area under the curve?
 one year ago
 one year ago

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apple_pi Group TitleBest ResponseYou've already chosen the best response.0
@experimentX @ParthKohli @mayankdevnani
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
The area between the graph of y = f(x) and the xaxis . This formula gives a positive result for a graph above the xaxis, and a negative result If the graph of y = f(x) is partly above and partly below the xaxis, the formula given below generates the net area. That is, the area above the axis minus the area below the axis.
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
http://www.mathwords.com/a/area_under_a_curve.htm
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
"Why is it that when you integrate a function" This is a little bit broad (there are functions that u can integrate that do not give the area under "the" curve). Maybe you mean over an interval....
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
dw:1350736162407:dw
 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
Area has a unit of meters squared, right? (m^2) So in order to do that, we have a function with a bunch of lengths. Since there are an infinite amount of points on a graph, we do magical calculus trickery and multiply each point on the graph by it's infinitesimally small width that's nearly 0 but isn't. Then we add them all up and get the area under the curve. So for example, if we have the graph y=2x and want to know the area under the curve from 1 to 3 we would set up this: \[\int\limits_{1}^{3}2x*dx\] Give yourself a second to really admire what's going on here. The big "S" is literally the letter S and it means "sum" all the areas from 1 to 3. And inside we see that we have 2x which is a height and dx which is a width, giving you an area. Now if we were to do this by hand (which is impossible) we would just start saying: (2*1)*dx+(2*1.00000001)*dx+(2*1.00000002)*dx+(2*1.00000003)*dx+... until we got to 3. Of course, I showed the decimals as ending at around 7 decimal spaces, but really that's just to convey the idea across since there are really points between the ones I'm adding up there. So magically we add up an infinite number of rectangles with infinitely small area and somehow it's becomes a real area, pretty weird. Another example to show that it's an area, let's consider the square here and find the area with both geometry and calculus!
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
in fact you do not you get the area under the curve if the function is positive it is an fact the definition of the area, the limiting value of sum of the area of the rectangles as the bases gets smaller and smaller
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
*it is IN FACT the definition of the area"
 one year ago
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