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experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1350734665748:dw

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0yes ... tension always has unit of force ... except for surface tension.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0First case: Σ F = mg mg  T = mg T = 0

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Second case: Σ F = ma mg  T = ma T = m (ga) = m(g5) Unit: N for first and second case.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0But..... but.... but.... the reel.... Shouldn't I take it into consideration??

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0you get acceleration after considering the rotational motion of reel. it shouldn't make any difference.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0in other words you have already taken care of rotational motion of reel. still if you need to verity then ... T*R = torque being applied on reel.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0sorry .. mg*R  TR = torque being applied on reel ... that makes it go round.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0mg*R  TR < this part creates motion.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0acc. of the reel = acc. of the mass?

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0no ... the reel does not have linear acceleration. It's rotating ... it has angular acceleration.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0tangential acc. of the reel = acc. of teh mass?

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0yes ... maybe ... worth checking it out.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0If we don't have the acc. of the reel, how can we suppose to find torque, so that we can find tension!?

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0well .. we have to find the acceleration reel first.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0or acceleration of the mass falling down first.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0using conservation of energy \[ {1 \over 2} mv^2 + {1 \over 2}I \omega^2 = mgh \\ \omega r = v,\] solving those two will give you final velocity, you know distance 'd', and initial velocity.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0solve for acceleration of the using it.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Wow! We're doing it backward!

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0That's not a problem :P

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0the other way ... "tangential acc. of the reel = acc. of teh mass" ... at the circumference of reel ... they go foot to foot.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Yes. Then we can find the angular acc. Using integration to find the moment of inertia, and then use it to find the torque. Is it possible?

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0yep .. this is also possible.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0For the energy one, can we really use that way?

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0sure ... the torque will always be constant ... hence there will be constant acceleration.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0I'm sorry, but how do I know if the torque is constant?

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0the torque depends on two parameters \( r \times F\) , F is part of mgh while r is radius of wheel. both are not changing ... neither is their angle between them.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0mgh?! the PE of the reel or..?!

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0mass .. hold on ... there seems to be discrepancy with second method.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1350737767080:dw

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1350737955528:dw

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Hmm.. So, you're just considering the mass m ..?

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1350738106593:dw