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estudier Group Title

Side length of equilateral triangle? (I have to draw it)

  • one year ago
  • one year ago

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  1. estudier Group Title
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    |dw:1350739907443:dw|

    • one year ago
  2. sauravshakya Group Title
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    U mean length of BC

    • one year ago
  3. estudier Group Title
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    yes, ABC is equilateral so any side...

    • one year ago
  4. sara12345 Group Title
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    4/sqrt(3) ?

    • one year ago
  5. estudier Group Title
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    Sorry, try again...

    • one year ago
  6. sara12345 Group Title
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    4 + 2/sqrt(3)

    • one year ago
  7. estudier Group Title
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    Um...no.

    • one year ago
  8. sara12345 Group Title
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    |dw:1350740356848:dw|

    • one year ago
  9. sara12345 Group Title
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    |dw:1350740418399:dw|

    • one year ago
  10. sara12345 Group Title
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    |dw:1350740461276:dw|

    • one year ago
  11. estudier Group Title
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    How u get 30?

    • one year ago
  12. estudier Group Title
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    Hint - make a transformation

    • one year ago
  13. sara12345 Group Title
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    i wasnt thinkin g sorry.. .let me think

    • one year ago
  14. estudier Group Title
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    U didn't like my hint?

    • one year ago
  15. estudier Group Title
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    No!

    • one year ago
  16. estudier Group Title
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    Imagine that the slant line is the x-axis and shift the triangle "up" 2 so that A is at the origin. Now try it...

    • one year ago
  17. sara12345 Group Title
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    trying

    • one year ago
  18. estudier Group Title
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    U see what I mean? Now if you drop the perpendiculars from B and C, they will 5 and 4

    • one year ago
  19. sara12345 Group Title
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    dont post any more hints.. plz

    • one year ago
  20. estudier Group Title
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    |dw:1350742011463:dw|

    • one year ago
  21. Kashan Group Title
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    4 sqrt 2

    • one year ago
  22. estudier Group Title
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    Nope, sorry.

    • one year ago
  23. estudier Group Title
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    I'm getting worried now, I better check my answer... This is Pythagorus and some algebra, right?

    • one year ago
  24. sara12345 Group Title
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    im getting 3 quadratics wid 3 variables

    • one year ago
  25. sauravshakya Group Title
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    |dw:1350743128666:dw|

    • one year ago
  26. sauravshakya Group Title
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    I guess Now, using cosine rule and sine rule will give x and y.

    • one year ago
  27. estudier Group Title
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    |dw:1350743084775:dw|

    • one year ago
  28. sauravshakya Group Title
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    is it 6.4291 ?

    • one year ago
  29. estudier Group Title
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    I have 2 sqrt 7

    • one year ago
  30. estudier Group Title
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    First 2 equations give s^2-t^2 = 9 Second and third give s^2 -2st =24 t = (s^2-24)/2s substitute in s^2-t^2 gives a quadratic in s etc.

    • one year ago
  31. estudier Group Title
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    I think Sara was closest...

    • one year ago
  32. sauravshakya Group Title
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    • one year ago
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  33. sauravshakya Group Title
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    Where did I go wrong???

    • one year ago
  34. estudier Group Title
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    I will have a look later on.....

    • one year ago
  35. sauravshakya Group Title
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    okay!

    • one year ago
  36. sauravshakya Group Title
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    Thanx @shubhamsrg AND yes there was a mistake in cosine law. Now, that gives the length 5.2915

    • one year ago
  37. sauravshakya Group Title
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    Which looks correct.

    • one year ago
  38. shubhamsrg Group Title
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    you did all the work buddy,, as i said,,a human error..i do more mistakes than that in my work.,, anyways,,good job YET AGAIN>>

    • one year ago
  39. estudier Group Title
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    Ah, u found it, good:-)

    • one year ago
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