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can you confirm the solution is the empty set?
2 included in 1 and not the other so nothing in common.
An arbitrary element \(\phi\) will always fulfil the condition \(\phi <2\) in set \((1,2)\). An arbitrary element \(\psi\) will always fulfil the condition \(\psi \ge 2 \) in set \([2,3)\). So, \(\rm \psi \ge 2>\phi\). Therefore, there is no common element.

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Other answers:

They are not really sets....
They are. :p
intervals
Intervals are sets.
an interval in set on an infinite number of points
@ParthKohli (1,2) What set is this?
{1.000000000000.....1, 1.000000......2 ..... 1.99999999999999........9}
Maybe, it wasn't actually defined...
\[x\in\mathbb R[1
The interval (1,2) can be interpreted as a set containing numbers between and not including 1 and 2.
\[(1,2)=\{x\in\mathbb{R}|1
Yes, the set builder notation.
yeah
thats what i ment @Zarkon
In this case, we have \(\phi \) instead.\[(1,2) = \{\phi \in \mathbb R |1<\phi <2\}\]Doesn't make a lot of difference either...
what is phi?
An arbitrary element in \((1,2)\).
Or if you're asking it that way, phi is a Greek letter.
strange choice of dummy variable
Greece is a country located in the east, precisely the Asian continent.
i did not know that
so i was right? \[(1,2)\cap[2,3)=\emptyset\]
It's actually in Eurasia - Europe.
Yes, my lad.
not you
I wasn't right? I was.
I said u were right back on the second post...
you dont know which way is east parth
Eastern Hemisphere. Okay?
ok
thanks all,
You're welcome.

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