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ienarancillo

  • 3 years ago

Given quadrilateral ABCD with AB = 47, BC = 31, CD = 61, angle B = 117 deg and angle C = 76 deg. FIND: 1. AD 2. angle A 3. angle D 4. AC 5. BD NEED YOUR HELP PLEASE! GONNA PASS THIS TOMORROW! THANKYOU!

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  1. ajprincess
    • 3 years ago
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    Have u got a diagram for this @ienarancillo?

  2. ienarancillo
    • 3 years ago
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    no @ajprincess . :( sorry. it's my homework and i really can't understand. PLEASE HELP

  3. ienarancillo
    • 3 years ago
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    last one please. @ajprincess In the figure, DB =16, angle BAD = 13 deg and angle ABD = 22 deg. Solve for CD. THANKYOU!

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  4. ienarancillo
    • 3 years ago
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    @Callisto please help. :'(

  5. Callisto
    • 3 years ago
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    Are you posting two questions here?

  6. ienarancillo
    • 3 years ago
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    yes sir. :)

  7. Callisto
    • 3 years ago
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    Not sir :S I'm not a guy. Please do not post two questions in a single post! For the first question, since the diagram is not given, we need to draw one ourselves. |dw:1350743930628:dw| Step 1: find BD, can you?

  8. ienarancillo
    • 3 years ago
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    OMG! sorry! i didn't mean to! :'(

  9. Callisto
    • 3 years ago
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    It's okay :) Can you find BD?

  10. Callisto
    • 3 years ago
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    By considering triangle BCD.

  11. ienarancillo
    • 3 years ago
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    i'm going to try solving it now. :)

  12. Callisto
    • 3 years ago
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    Tell me if you need some hints or so.

  13. ienarancillo
    • 3 years ago
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    can i have a hint please. i am very confused in finding the angles which are along the transversal lines. :(

  14. Callisto
    • 3 years ago
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    Use cosine law. a^2 = b^2 + c^2 - 2bc cosA

  15. ienarancillo
    • 3 years ago
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    awww. thanks.

  16. Callisto
    • 3 years ago
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    Can you find BD now?

  17. ienarancillo
    • 3 years ago
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    so.. i drew a separate triangle for this.

  18. ienarancillo
    • 3 years ago
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    \[\sqrt{76^{2}+31^{2}-2(76)(31)\cos(76)}\] = 69.7 BD = 69.7

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  19. ienarancillo
    • 3 years ago
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    sorry it took so long. :"(

  20. ienarancillo
    • 3 years ago
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    @Callisto Is this correct? please help.

  21. Callisto
    • 3 years ago
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    Is CD = 6 or 76??

  22. ienarancillo
    • 3 years ago
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    CD = 61 :)

  23. Callisto
    • 3 years ago
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    You typed CD = 6 :S Anyway. No, it's not correct though :|

  24. ienarancillo
    • 3 years ago
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    OMG! so sorry again! :(

  25. ienarancillo
    • 3 years ago
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    then what should i do next? :)

  26. ienarancillo
    • 3 years ago
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    how should i find the angles? :)

  27. Callisto
    • 3 years ago
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    You have to find BD first, and the BD you found is not right. Plug in 61 instead of 76

  28. ienarancillo
    • 3 years ago
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    oh. sorry. is it 61.4? @Callisto

  29. Callisto
    • 3 years ago
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    Yup. Next step: Find angle CBD

  30. ienarancillo
    • 3 years ago
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    i used sine law for this. \[\frac{ \sin 76 }{ 61.4 } \frac{ \sin \angle CBD }{ 61 } = 74.6 degrees\]

  31. ienarancillo
    • 3 years ago
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    @Callisto is this it? :)

  32. Callisto
    • 3 years ago
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    Yup. So, now, find angle ABD.

  33. ienarancillo
    • 3 years ago
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    11- 61.4 = 42.4 :)

  34. ienarancillo
    • 3 years ago
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    i menat 117 - 61.4 = 42.4

  35. ienarancillo
    • 3 years ago
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    *meant

  36. ienarancillo
    • 3 years ago
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    @Callisto what should i do next? thanks so much for ur help.

  37. Callisto
    • 3 years ago
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    Next?! Find AD :D By considering triangle ABD.

  38. ienarancillo
    • 3 years ago
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    sorry. honestly, i ought to do the same thing. :D

  39. Callisto
    • 3 years ago
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    Hmmm you mean?

  40. ienarancillo
    • 3 years ago
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    uhmm, i was solving it before you replied. i asked you just to be sure. :D is this correct? :) @Callisto

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  41. Callisto
    • 3 years ago
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    Wait. It should be 117 - 74.6 = 42.4 And the answer you've got is wrong..

  42. ienarancillo
    • 3 years ago
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    OMG. so sorry again, i just typed it wrong. but i guess, 42.4 is right? :)

  43. Callisto
    • 3 years ago
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    Yes.

  44. ienarancillo
    • 3 years ago
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    and is my AD correct? :)

  45. Callisto
    • 3 years ago
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    I think so :|

  46. ienarancillo
    • 3 years ago
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    sorry. i'll sum up all the remaining 3 answers. im sorry to bother you. but im in the process of understanding it now. :)

  47. Callisto
    • 3 years ago
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    It's okay :) Glad that you're understanding it now :)

  48. ienarancillo
    • 3 years ago
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    are my answers correct? :)

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  49. ienarancillo
    • 3 years ago
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    @Callisto :D

  50. Callisto
    • 3 years ago
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    Wait... AD isn't 41.8

  51. Callisto
    • 3 years ago
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    It's close to 41.8, but not 41.8

  52. ienarancillo
    • 3 years ago
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    carelessness of mine. it's 41.4? :O

  53. Callisto
    • 3 years ago
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    Yes!

  54. ienarancillo
    • 3 years ago
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    but it's math error when i'm solving for angle a.

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  55. Callisto
    • 3 years ago
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    It should be sin A/ BD = sin angleABD / AD

  56. ienarancillo
    • 3 years ago
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    yes. i did that. \[\frac{ \sin \angle A }{ 61.4 }\frac{ \sin 42.4 }{ 41.4 } = MATH ERROR\]

  57. Callisto
    • 3 years ago
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    Hmm.. can you round your answer above to 4 d.p.? That way, you can get the answer!

  58. ienarancillo
    • 3 years ago
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    uhmm, our instruction says 'all answers must be rounded off to the tenths place'. :'(

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