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ienarancillo Group Title

Given quadrilateral ABCD with AB = 47, BC = 31, CD = 61, angle B = 117 deg and angle C = 76 deg. FIND: 1. AD 2. angle A 3. angle D 4. AC 5. BD NEED YOUR HELP PLEASE! GONNA PASS THIS TOMORROW! THANKYOU!

  • one year ago
  • one year ago

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  1. ajprincess Group Title
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    Have u got a diagram for this @ienarancillo?

    • one year ago
  2. ienarancillo Group Title
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    no @ajprincess . :( sorry. it's my homework and i really can't understand. PLEASE HELP

    • one year ago
  3. ienarancillo Group Title
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    last one please. @ajprincess In the figure, DB =16, angle BAD = 13 deg and angle ABD = 22 deg. Solve for CD. THANKYOU!

    • one year ago
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  4. ienarancillo Group Title
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    @Callisto please help. :'(

    • one year ago
  5. Callisto Group Title
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    Are you posting two questions here?

    • one year ago
  6. ienarancillo Group Title
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    yes sir. :)

    • one year ago
  7. Callisto Group Title
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    Not sir :S I'm not a guy. Please do not post two questions in a single post! For the first question, since the diagram is not given, we need to draw one ourselves. |dw:1350743930628:dw| Step 1: find BD, can you?

    • one year ago
  8. ienarancillo Group Title
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    OMG! sorry! i didn't mean to! :'(

    • one year ago
  9. Callisto Group Title
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    It's okay :) Can you find BD?

    • one year ago
  10. Callisto Group Title
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    By considering triangle BCD.

    • one year ago
  11. ienarancillo Group Title
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    i'm going to try solving it now. :)

    • one year ago
  12. Callisto Group Title
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    Tell me if you need some hints or so.

    • one year ago
  13. ienarancillo Group Title
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    can i have a hint please. i am very confused in finding the angles which are along the transversal lines. :(

    • one year ago
  14. Callisto Group Title
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    Use cosine law. a^2 = b^2 + c^2 - 2bc cosA

    • one year ago
  15. ienarancillo Group Title
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    awww. thanks.

    • one year ago
  16. Callisto Group Title
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    Can you find BD now?

    • one year ago
  17. ienarancillo Group Title
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    so.. i drew a separate triangle for this.

    • one year ago
  18. ienarancillo Group Title
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    \[\sqrt{76^{2}+31^{2}-2(76)(31)\cos(76)}\] = 69.7 BD = 69.7

    • one year ago
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  19. ienarancillo Group Title
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    sorry it took so long. :"(

    • one year ago
  20. ienarancillo Group Title
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    @Callisto Is this correct? please help.

    • one year ago
  21. Callisto Group Title
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    Is CD = 6 or 76??

    • one year ago
  22. ienarancillo Group Title
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    CD = 61 :)

    • one year ago
  23. Callisto Group Title
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    You typed CD = 6 :S Anyway. No, it's not correct though :|

    • one year ago
  24. ienarancillo Group Title
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    OMG! so sorry again! :(

    • one year ago
  25. ienarancillo Group Title
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    then what should i do next? :)

    • one year ago
  26. ienarancillo Group Title
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    how should i find the angles? :)

    • one year ago
  27. Callisto Group Title
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    You have to find BD first, and the BD you found is not right. Plug in 61 instead of 76

    • one year ago
  28. ienarancillo Group Title
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    oh. sorry. is it 61.4? @Callisto

    • one year ago
  29. Callisto Group Title
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    Yup. Next step: Find angle CBD

    • one year ago
  30. ienarancillo Group Title
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    i used sine law for this. \[\frac{ \sin 76 }{ 61.4 } \frac{ \sin \angle CBD }{ 61 } = 74.6 degrees\]

    • one year ago
  31. ienarancillo Group Title
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    @Callisto is this it? :)

    • one year ago
  32. Callisto Group Title
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    Yup. So, now, find angle ABD.

    • one year ago
  33. ienarancillo Group Title
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    11- 61.4 = 42.4 :)

    • one year ago
  34. ienarancillo Group Title
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    i menat 117 - 61.4 = 42.4

    • one year ago
  35. ienarancillo Group Title
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    *meant

    • one year ago
  36. ienarancillo Group Title
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    @Callisto what should i do next? thanks so much for ur help.

    • one year ago
  37. Callisto Group Title
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    Next?! Find AD :D By considering triangle ABD.

    • one year ago
  38. ienarancillo Group Title
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    sorry. honestly, i ought to do the same thing. :D

    • one year ago
  39. Callisto Group Title
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    Hmmm you mean?

    • one year ago
  40. ienarancillo Group Title
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    uhmm, i was solving it before you replied. i asked you just to be sure. :D is this correct? :) @Callisto

    • one year ago
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  41. Callisto Group Title
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    Wait. It should be 117 - 74.6 = 42.4 And the answer you've got is wrong..

    • one year ago
  42. ienarancillo Group Title
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    OMG. so sorry again, i just typed it wrong. but i guess, 42.4 is right? :)

    • one year ago
  43. Callisto Group Title
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    Yes.

    • one year ago
  44. ienarancillo Group Title
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    and is my AD correct? :)

    • one year ago
  45. Callisto Group Title
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    I think so :|

    • one year ago
  46. ienarancillo Group Title
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    sorry. i'll sum up all the remaining 3 answers. im sorry to bother you. but im in the process of understanding it now. :)

    • one year ago
  47. Callisto Group Title
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    It's okay :) Glad that you're understanding it now :)

    • one year ago
  48. ienarancillo Group Title
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    are my answers correct? :)

    • one year ago
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  49. ienarancillo Group Title
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    @Callisto :D

    • one year ago
  50. Callisto Group Title
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    Wait... AD isn't 41.8

    • one year ago
  51. Callisto Group Title
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    It's close to 41.8, but not 41.8

    • one year ago
  52. ienarancillo Group Title
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    carelessness of mine. it's 41.4? :O

    • one year ago
  53. Callisto Group Title
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    Yes!

    • one year ago
  54. ienarancillo Group Title
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    but it's math error when i'm solving for angle a.

    • one year ago
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  55. Callisto Group Title
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    It should be sin A/ BD = sin angleABD / AD

    • one year ago
  56. ienarancillo Group Title
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    yes. i did that. \[\frac{ \sin \angle A }{ 61.4 }\frac{ \sin 42.4 }{ 41.4 } = MATH ERROR\]

    • one year ago
  57. Callisto Group Title
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    Hmm.. can you round your answer above to 4 d.p.? That way, you can get the answer!

    • one year ago
  58. ienarancillo Group Title
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    uhmm, our instruction says 'all answers must be rounded off to the tenths place'. :'(

    • one year ago
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