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Given quadrilateral ABCD with AB = 47, BC = 31, CD = 61, angle B = 117 deg and angle C = 76 deg. FIND: 1. AD 2. angle A 3. angle D 4. AC 5. BD NEED YOUR HELP PLEASE! GONNA PASS THIS TOMORROW! THANKYOU!

Trigonometry
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Have u got a diagram for this @ienarancillo?
no @ajprincess . :( sorry. it's my homework and i really can't understand. PLEASE HELP
last one please. @ajprincess In the figure, DB =16, angle BAD = 13 deg and angle ABD = 22 deg. Solve for CD. THANKYOU!
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Other answers:

@Callisto please help. :'(
Are you posting two questions here?
yes sir. :)
Not sir :S I'm not a guy. Please do not post two questions in a single post! For the first question, since the diagram is not given, we need to draw one ourselves. |dw:1350743930628:dw| Step 1: find BD, can you?
OMG! sorry! i didn't mean to! :'(
It's okay :) Can you find BD?
By considering triangle BCD.
i'm going to try solving it now. :)
Tell me if you need some hints or so.
can i have a hint please. i am very confused in finding the angles which are along the transversal lines. :(
Use cosine law. a^2 = b^2 + c^2 - 2bc cosA
awww. thanks.
Can you find BD now?
so.. i drew a separate triangle for this.
\[\sqrt{76^{2}+31^{2}-2(76)(31)\cos(76)}\] = 69.7 BD = 69.7
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sorry it took so long. :"(
@Callisto Is this correct? please help.
Is CD = 6 or 76??
CD = 61 :)
You typed CD = 6 :S Anyway. No, it's not correct though :|
OMG! so sorry again! :(
then what should i do next? :)
how should i find the angles? :)
You have to find BD first, and the BD you found is not right. Plug in 61 instead of 76
oh. sorry. is it 61.4? @Callisto
Yup. Next step: Find angle CBD
i used sine law for this. \[\frac{ \sin 76 }{ 61.4 } \frac{ \sin \angle CBD }{ 61 } = 74.6 degrees\]
@Callisto is this it? :)
Yup. So, now, find angle ABD.
11- 61.4 = 42.4 :)
i menat 117 - 61.4 = 42.4
*meant
@Callisto what should i do next? thanks so much for ur help.
Next?! Find AD :D By considering triangle ABD.
sorry. honestly, i ought to do the same thing. :D
Hmmm you mean?
uhmm, i was solving it before you replied. i asked you just to be sure. :D is this correct? :) @Callisto
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Wait. It should be 117 - 74.6 = 42.4 And the answer you've got is wrong..
OMG. so sorry again, i just typed it wrong. but i guess, 42.4 is right? :)
Yes.
and is my AD correct? :)
I think so :|
sorry. i'll sum up all the remaining 3 answers. im sorry to bother you. but im in the process of understanding it now. :)
It's okay :) Glad that you're understanding it now :)
are my answers correct? :)
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Wait... AD isn't 41.8
It's close to 41.8, but not 41.8
carelessness of mine. it's 41.4? :O
Yes!
but it's math error when i'm solving for angle a.
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It should be sin A/ BD = sin angleABD / AD
yes. i did that. \[\frac{ \sin \angle A }{ 61.4 }\frac{ \sin 42.4 }{ 41.4 } = MATH ERROR\]
Hmm.. can you round your answer above to 4 d.p.? That way, you can get the answer!
uhmm, our instruction says 'all answers must be rounded off to the tenths place'. :'(

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