Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

|dw:1350749050460:dw|
Just product rule term by term! Start with u = x² -> u' = ...?
|dw:1350749192642:dw|

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

?
power rule and then e^x is e^x
i am not sure
If you're unsure, so please don't jump ahead! You have your choices: following my guidance by fill in the blanks or show your work completely :)
|dw:1350749473100:dw|
i took the power rule so it is 2x and e^x is e^x
Then where is your PRODUCT rule for the first term?
hmm ok |dw:1350749608453:dw|
|dw:1350749664511:dw|
is this correct
I'm lost, totally :( Now, you should follow my guiding: For the first term: u = x² --> u' = v = e^x --> v' = => u' v + uv' = ....
|dw:1350750048815:dw|
|dw:1350750099466:dw|
Yes, at least some light shining out of the tunnel here :)
so whats next
|dw:1350750252467:dw|
so this is answer
Make it neat, so you can easily simplify them: ( x²e^x + 2x e^x ) - ( x e^x + e^x) = e^x ( x² + 2x - x - 1) = e^x ( x² + x - 1)
i used the same formula for this one but i did not get
|dw:1350750484771:dw|
Does it look simple enough?
yup
|dw:1350750529693:dw|
this is wrong but i dont know where i did the mistake
So don't make it complicated by jumping all over, make each line is worthy effort :)
x^2(e^x) - x(e^x) ... make your life simple, pull out e^x
e^x * (x^2 - x), now use the product rule
e^x * (2x-1) + (x^2 - x) * e^x
Now simplify, pull out e^x again: e^x (2x - 1 + x^2 - x) = e^x (x^2 + x - 1)
Now, you can either leave it like that, or distribute e^x. If you choose to do the latter, e^x * x^2 + e^x * x - e^x
what about this one |dw:1350751090719:dw|
if i take the product rule the e^2
|dw:1350751424118:dw|
can u plz help with this

Not the answer you are looking for?

Search for more explanations.

Ask your own question