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ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1350749050460:dw
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.2
Just product rule term by term! Start with u = x² > u' = ...?
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1350749192642:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
power rule and then e^x is e^x
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i am not sure
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
@Chlorophyll
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.2
If you're unsure, so please don't jump ahead! You have your choices: following my guidance by fill in the blanks or show your work completely :)
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1350749473100:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i took the power rule so it is 2x and e^x is e^x
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.2
Then where is your PRODUCT rule for the first term?
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
hmm ok dw:1350749608453:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1350749664511:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
is this correct
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.2
I'm lost, totally :( Now, you should follow my guiding: For the first term: u = x² > u' = v = e^x > v' = => u' v + uv' = ....
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1350750048815:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1350750099466:dw
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.2
Yes, at least some light shining out of the tunnel here :)
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
so whats next
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1350750252467:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
so this is answer
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.2
Make it neat, so you can easily simplify them: ( x²e^x + 2x e^x )  ( x e^x + e^x) = e^x ( x² + 2x  x  1) = e^x ( x² + x  1)
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i used the same formula for this one but i did not get
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1350750484771:dw
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.2
Does it look simple enough?
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1350750529693:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
this is wrong but i dont know where i did the mistake
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.2
So don't make it complicated by jumping all over, make each line is worthy effort :)
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
x^2(e^x)  x(e^x) ... make your life simple, pull out e^x
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
e^x * (x^2  x), now use the product rule
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
e^x * (2x1) + (x^2  x) * e^x
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
Now simplify, pull out e^x again: e^x (2x  1 + x^2  x) = e^x (x^2 + x  1)
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
Now, you can either leave it like that, or distribute e^x. If you choose to do the latter, e^x * x^2 + e^x * x  e^x
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
what about this one dw:1350751090719:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
@Chlorophyll
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
if i take the product rule the e^2
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1350751424118:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
can u plz help with this
 2 years ago
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