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ksaimouliBest ResponseYou've already chosen the best response.0
dw:1350749050460:dw
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.2
Just product rule term by term! Start with u = x² > u' = ...?
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1350749192642:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
power rule and then e^x is e^x
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.2
If you're unsure, so please don't jump ahead! You have your choices: following my guidance by fill in the blanks or show your work completely :)
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1350749473100:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
i took the power rule so it is 2x and e^x is e^x
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.2
Then where is your PRODUCT rule for the first term?
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
hmm ok dw:1350749608453:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1350749664511:dw
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.2
I'm lost, totally :( Now, you should follow my guiding: For the first term: u = x² > u' = v = e^x > v' = => u' v + uv' = ....
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1350750048815:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1350750099466:dw
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.2
Yes, at least some light shining out of the tunnel here :)
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1350750252467:dw
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.2
Make it neat, so you can easily simplify them: ( x²e^x + 2x e^x )  ( x e^x + e^x) = e^x ( x² + 2x  x  1) = e^x ( x² + x  1)
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
i used the same formula for this one but i did not get
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1350750484771:dw
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.2
Does it look simple enough?
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1350750529693:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
this is wrong but i dont know where i did the mistake
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.2
So don't make it complicated by jumping all over, make each line is worthy effort :)
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.1
x^2(e^x)  x(e^x) ... make your life simple, pull out e^x
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.1
e^x * (x^2  x), now use the product rule
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.1
e^x * (2x1) + (x^2  x) * e^x
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.1
Now simplify, pull out e^x again: e^x (2x  1 + x^2  x) = e^x (x^2 + x  1)
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.1
Now, you can either leave it like that, or distribute e^x. If you choose to do the latter, e^x * x^2 + e^x * x  e^x
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
what about this one dw:1350751090719:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
if i take the product rule the e^2
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1350751424118:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
can u plz help with this
 one year ago
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