Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ksaimouli Group Title

dy/dx

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350749050460:dw|

    • 2 years ago
  2. Chlorophyll Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Just product rule term by term! Start with u = x² -> u' = ...?

    • 2 years ago
  3. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350749192642:dw|

    • 2 years ago
  4. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

    • 2 years ago
  5. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    power rule and then e^x is e^x

    • 2 years ago
  6. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i am not sure

    • 2 years ago
  7. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @Chlorophyll

    • 2 years ago
  8. Chlorophyll Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    If you're unsure, so please don't jump ahead! You have your choices: following my guidance by fill in the blanks or show your work completely :)

    • 2 years ago
  9. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350749473100:dw|

    • 2 years ago
  10. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i took the power rule so it is 2x and e^x is e^x

    • 2 years ago
  11. Chlorophyll Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Then where is your PRODUCT rule for the first term?

    • 2 years ago
  12. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    hmm ok |dw:1350749608453:dw|

    • 2 years ago
  13. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350749664511:dw|

    • 2 years ago
  14. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    is this correct

    • 2 years ago
  15. Chlorophyll Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    I'm lost, totally :( Now, you should follow my guiding: For the first term: u = x² --> u' = v = e^x --> v' = => u' v + uv' = ....

    • 2 years ago
  16. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350750048815:dw|

    • 2 years ago
  17. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350750099466:dw|

    • 2 years ago
  18. Chlorophyll Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Yes, at least some light shining out of the tunnel here :)

    • 2 years ago
  19. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    so whats next

    • 2 years ago
  20. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350750252467:dw|

    • 2 years ago
  21. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    so this is answer

    • 2 years ago
  22. Chlorophyll Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Make it neat, so you can easily simplify them: ( x²e^x + 2x e^x ) - ( x e^x + e^x) = e^x ( x² + 2x - x - 1) = e^x ( x² + x - 1)

    • 2 years ago
  23. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i used the same formula for this one but i did not get

    • 2 years ago
  24. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350750484771:dw|

    • 2 years ago
  25. Chlorophyll Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Does it look simple enough?

    • 2 years ago
  26. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yup

    • 2 years ago
  27. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350750529693:dw|

    • 2 years ago
  28. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    this is wrong but i dont know where i did the mistake

    • 2 years ago
  29. Chlorophyll Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    So don't make it complicated by jumping all over, make each line is worthy effort :)

    • 2 years ago
  30. bahrom7893 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    x^2(e^x) - x(e^x) ... make your life simple, pull out e^x

    • 2 years ago
  31. bahrom7893 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    e^x * (x^2 - x), now use the product rule

    • 2 years ago
  32. bahrom7893 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    e^x * (2x-1) + (x^2 - x) * e^x

    • 2 years ago
  33. bahrom7893 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Now simplify, pull out e^x again: e^x (2x - 1 + x^2 - x) = e^x (x^2 + x - 1)

    • 2 years ago
  34. bahrom7893 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Now, you can either leave it like that, or distribute e^x. If you choose to do the latter, e^x * x^2 + e^x * x - e^x

    • 2 years ago
  35. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    what about this one |dw:1350751090719:dw|

    • 2 years ago
  36. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @Chlorophyll

    • 2 years ago
  37. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    if i take the product rule the e^2

    • 2 years ago
  38. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350751424118:dw|

    • 2 years ago
  39. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    can u plz help with this

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.