ksaimouli
  • ksaimouli
dy/dx
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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ksaimouli
  • ksaimouli
|dw:1350749050460:dw|
anonymous
  • anonymous
Just product rule term by term! Start with u = x² -> u' = ...?
ksaimouli
  • ksaimouli
|dw:1350749192642:dw|

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More answers

ksaimouli
  • ksaimouli
?
ksaimouli
  • ksaimouli
power rule and then e^x is e^x
ksaimouli
  • ksaimouli
i am not sure
ksaimouli
  • ksaimouli
@Chlorophyll
anonymous
  • anonymous
If you're unsure, so please don't jump ahead! You have your choices: following my guidance by fill in the blanks or show your work completely :)
ksaimouli
  • ksaimouli
|dw:1350749473100:dw|
ksaimouli
  • ksaimouli
i took the power rule so it is 2x and e^x is e^x
anonymous
  • anonymous
Then where is your PRODUCT rule for the first term?
ksaimouli
  • ksaimouli
hmm ok |dw:1350749608453:dw|
ksaimouli
  • ksaimouli
|dw:1350749664511:dw|
ksaimouli
  • ksaimouli
is this correct
anonymous
  • anonymous
I'm lost, totally :( Now, you should follow my guiding: For the first term: u = x² --> u' = v = e^x --> v' = => u' v + uv' = ....
ksaimouli
  • ksaimouli
|dw:1350750048815:dw|
ksaimouli
  • ksaimouli
|dw:1350750099466:dw|
anonymous
  • anonymous
Yes, at least some light shining out of the tunnel here :)
ksaimouli
  • ksaimouli
so whats next
ksaimouli
  • ksaimouli
|dw:1350750252467:dw|
ksaimouli
  • ksaimouli
so this is answer
anonymous
  • anonymous
Make it neat, so you can easily simplify them: ( x²e^x + 2x e^x ) - ( x e^x + e^x) = e^x ( x² + 2x - x - 1) = e^x ( x² + x - 1)
ksaimouli
  • ksaimouli
i used the same formula for this one but i did not get
ksaimouli
  • ksaimouli
|dw:1350750484771:dw|
anonymous
  • anonymous
Does it look simple enough?
ksaimouli
  • ksaimouli
yup
ksaimouli
  • ksaimouli
|dw:1350750529693:dw|
ksaimouli
  • ksaimouli
this is wrong but i dont know where i did the mistake
anonymous
  • anonymous
So don't make it complicated by jumping all over, make each line is worthy effort :)
bahrom7893
  • bahrom7893
x^2(e^x) - x(e^x) ... make your life simple, pull out e^x
bahrom7893
  • bahrom7893
e^x * (x^2 - x), now use the product rule
bahrom7893
  • bahrom7893
e^x * (2x-1) + (x^2 - x) * e^x
bahrom7893
  • bahrom7893
Now simplify, pull out e^x again: e^x (2x - 1 + x^2 - x) = e^x (x^2 + x - 1)
bahrom7893
  • bahrom7893
Now, you can either leave it like that, or distribute e^x. If you choose to do the latter, e^x * x^2 + e^x * x - e^x
ksaimouli
  • ksaimouli
what about this one |dw:1350751090719:dw|
ksaimouli
  • ksaimouli
@Chlorophyll
ksaimouli
  • ksaimouli
if i take the product rule the e^2
ksaimouli
  • ksaimouli
|dw:1350751424118:dw|
ksaimouli
  • ksaimouli
can u plz help with this

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