Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Copythat
Group Title
Draw a parallelogram whose adjacent sides are determined by the vectors [4,6] and [3,5]. Find the area of the parallelogram.
 one year ago
 one year ago
Copythat Group Title
Draw a parallelogram whose adjacent sides are determined by the vectors [4,6] and [3,5]. Find the area of the parallelogram.
 one year ago
 one year ago

This Question is Closed

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Isn't it dot product which finds the area?
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
You can use the origin (0,0) as the common start point for those two vectors; that would make it easiest to draw.
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
No, I don't think it's dot product, as dot product is a measure of how much the vectors are in each other's direction, so it would have high dottiness if they were like thisdw:1350760137445:dwbut very low area (dottiness=cos(angle between vectors))
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
Cross product most likely, but forget about the result being a vector.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Oh, that's right, cross product because it is a*b*sin(Θ).
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
b*sin(Θ) is the height of the parallelogram. Duh, should have remembered the basic trig on that one.
 one year ago

Copythat Group TitleBest ResponseYou've already chosen the best response.0
Is there any way to solve for the area without trig?
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Not really...
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Well, doing the crossproduct has the trig builtin, so you wouldn't actually be using a trig function explicitly.
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
I suppose you could try to use pythagoras
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
^ what do you mean? By stacking up right triangles and using subtraction?
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
dw:1350764732234:dw find B perpendicular with A by finding the 'gradient' of A... you can do it, but it's really fiddly
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
No there must be an elegant way of finding B perp A
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
as a function of Ax, Bx, Ay and By
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
I'd rather just do the crossproduct.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
\[\left[\begin{matrix}i & j & k \\ 4 & 6 & 0 \\ 3 & 5 & 0\end{matrix}\right] = 4\times5  6\times3=2\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.