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Prove the exterior angles theorem: Given: triangle ABC w/ exterior angle ACD Prove: measure of angle ACD= measure of angle A +measure of angle B. Please help! i dont know how to do this proof!
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if the sum of the angles is 180, then A + B + C = 180. Solving for C, you get C=180-A-B. For the exterior angle, angle DCA is supplementary to angle ACB. So, DCA + ACB = 180. SInce you know angle ACB (simplified to angle C in the first line), you can substitute that DCA+180-A-B=180. IF you simplify this, you get DCA=A+B