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richyw
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having a little bit of trouble remembering how to do the differential.
 2 years ago
 2 years ago
richyw Group Title
having a little bit of trouble remembering how to do the differential.
 2 years ago
 2 years ago

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richyw Group TitleBest ResponseYou've already chosen the best response.0
so I have \(k(x,y,z)=e^{x^2+y^2+z^2}\) where \(x=\sqrt{t+1},\;y=\sqrt{t^2+1},\:z=\sqrt{t^3+1}\) . Now i need to find \(\frac{dk}{dt}\).
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
to do this do I just say\[\frac{dk}{dt}=\frac{dk}{dx}\frac{dx}{dt}+\frac{dk}{dy}\frac{dy}{dt}+\frac{dk}{dz}\frac{dz}{dt}\]
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
I am getting an answer of \[\frac{dk}{dt}=2e^{t^3+t^2+t+3}\left(3t^2+2t+1\right)\] is this correct, and does anyone know how to check this on wolfram, or opensource math software?
 2 years ago

eseidl Group TitleBest ResponseYou've already chosen the best response.1
The formula for the total differential is correct, as long as the dk/dx,etc terms are partial derivatives.
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
yeah sorry I didn't want to type "partial" \(\partial\) in the latex that many times :)
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
thanks a lot. can anyone confirm this is the correct answer?
 2 years ago

eseidl Group TitleBest ResponseYou've already chosen the best response.1
this one is super tedious...give me a minute I'll do it with pen and paper...
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
alright thanks a lot. I really appreciate it.
 2 years ago

eseidl Group TitleBest ResponseYou've already chosen the best response.1
I get:\[e^{t^3+t^2+t+3}(3t^2+2t+1)\]
 2 years ago

eseidl Group TitleBest ResponseYou've already chosen the best response.1
Your factor of two should cancel when you differentiate the square root term (which gives you a 2 in the denominator)...
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
thanks a lot! I see I made a basic calculus mistake but am glad I remember this stuff!
 2 years ago
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