Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

oio Group Title

Hi! This question deals with derivatives Ok, here it is: The quantity demanded per month, y, of USEM tablets is related to the average price unit, p(t) (in dollars), of tablets by the equation y=f(p(t))= 10 * sqrt(810,000-[p(t)]^2) It is estimated that 3 months from now, the average price of the tablet will be given by p(t)= [400/(1+sqrt(t))] +500 (t is less than or equal to 60 and more than or equal to 0) I know I should use the Product and The Chain Rule, but I'm not sure how to apply it! Thank you in advance. I just need to find the derivative! I would really love an exp

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. saifoo.khan Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @dpaInc

    • 2 years ago
  2. oio Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[y=f(p(t))10\sqrt{810000-\left[ p \left( t \right) \right]^{2}}\] \[p(t)=\frac{ 400 }{ 1+\sqrt{t} }+500\] I hope this is more helpful :(

    • 2 years ago
  3. Shadowys Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I don't understand what the question wants. Two equations and that's it?

    • 2 years ago
  4. oio Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    oh whooop! AUGGHH! i forgot the rest hang on :) Find the rate at which the quantity of tablets deamnded per month will be changing 16 months from now!

    • 2 years ago
  5. oio Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks guys for helping me! :)

    • 2 years ago
  6. oio Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank you for replying at the moment

    • 2 years ago
  7. Shadowys Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    LOL sorry. You might notice that \[f(p(t))' = f'(p(t))* p'(t)\] And you have both. Now, for p(t), \[p'(t)=400(1+\sqrt t)^-1 +500\] To use the chain rule, you can let u =(1+\sqrt t)^-1

    • 2 years ago
  8. Shadowys Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    p′(t)=(400(1+t√)−1+500)' sorry mistype

    • 2 years ago
  9. oio Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you but...im still kind of confused... :( I really get confused when I derive f(p(t)) itself

    • 2 years ago
  10. Shadowys Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yup, you might want to let it as u before starting...

    • 2 years ago
  11. oio Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    uhm thanks :)

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.