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UnkleRhaukus
 3 years ago
\[\neg[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]]\iff\exists x[x\geq0\Rightarrow\forall y(y^2\neq x)]\]
UnkleRhaukus
 3 years ago
\[\neg[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]]\iff\exists x[x\geq0\Rightarrow\forall y(y^2\neq x)]\]

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UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2no wait , i see error

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2the negation of an implication

helder_edwin
 3 years ago
Best ResponseYou've already chosen the best response.1the negation of \(\to\) is \(\wedge\)

helder_edwin
 3 years ago
Best ResponseYou've already chosen the best response.1\[ \large \neg(p\to q)\equiv p\wedge\neg q \]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2\[\exists x[x<0\wedge\forall y(y^2\neq x)]\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ya that makes more sense

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmmm you edited your question but its still incorrect

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2\[\neg\left[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]\right]\iff\exists x\left[x<0\land\forall y(y^2\neq x)\right]\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2thanks to you both
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