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UnkleRhaukus
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\[\neg[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]]\iff\exists x[x\geq0\Rightarrow\forall y(y^2\neq x)]\]
 one year ago
 one year ago
UnkleRhaukus Group Title
\[\neg[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]]\iff\exists x[x\geq0\Rightarrow\forall y(y^2\neq x)]\]
 one year ago
 one year ago

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UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
am i right/
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
no wait , i see error
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
the negation of an implication
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
the negation of \(\to\) is \(\wedge\)
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
\[ \large \neg(p\to q)\equiv p\wedge\neg q \]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
\[\exists x[x<0\wedge\forall y(y^2\neq x)]\]
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Ya that makes more sense
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
hmmm you edited your question but its still incorrect
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
\[\neg\left[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]\right]\iff\exists x\left[x<0\land\forall y(y^2\neq x)\right]\]
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Yes thats the answer
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
thanks to you both
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
not that I helped :P
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
u r welcome
 one year ago
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