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UnkleRhaukus
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\[\neg[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]]\iff\exists x[x\geq0\Rightarrow\forall y(y^2\neq x)]\]
 2 years ago
 2 years ago
UnkleRhaukus Group Title
\[\neg[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]]\iff\exists x[x\geq0\Rightarrow\forall y(y^2\neq x)]\]
 2 years ago
 2 years ago

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UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
am i right/
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
no wait , i see error
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
the negation of an implication
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
the negation of \(\to\) is \(\wedge\)
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
\[ \large \neg(p\to q)\equiv p\wedge\neg q \]
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
\[\exists x[x<0\wedge\forall y(y^2\neq x)]\]
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Ya that makes more sense
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
hmmm you edited your question but its still incorrect
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
\[\neg\left[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]\right]\iff\exists x\left[x<0\land\forall y(y^2\neq x)\right]\]
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Yes thats the answer
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
thanks to you both
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
not that I helped :P
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
u r welcome
 2 years ago
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