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UnkleRhaukus

  • 3 years ago

\[\neg[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]]\iff\exists x[x\geq0\Rightarrow\forall y(y^2\neq x)]\]

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  1. UnkleRhaukus
    • 3 years ago
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    am i right/

  2. UnkleRhaukus
    • 3 years ago
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    no wait , i see error

  3. UnkleRhaukus
    • 3 years ago
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    the negation of an implication

  4. helder_edwin
    • 3 years ago
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    the negation of \(\to\) is \(\wedge\)

  5. UnkleRhaukus
    • 3 years ago
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    yeah

  6. helder_edwin
    • 3 years ago
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    \[ \large \neg(p\to q)\equiv p\wedge\neg q \]

  7. UnkleRhaukus
    • 3 years ago
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    \[\exists x[x<0\wedge\forall y(y^2\neq x)]\]

  8. swissgirl
    • 3 years ago
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    Ya that makes more sense

  9. swissgirl
    • 3 years ago
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    hmmm you edited your question but its still incorrect

  10. UnkleRhaukus
    • 3 years ago
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    \[\neg\left[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]\right]\iff\exists x\left[x<0\land\forall y(y^2\neq x)\right]\]

  11. swissgirl
    • 3 years ago
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    Yes thats the answer

  12. UnkleRhaukus
    • 3 years ago
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    thanks to you both

  13. swissgirl
    • 3 years ago
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    not that I helped :P

  14. helder_edwin
    • 3 years ago
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    u r welcome

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