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\[\neg[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]]\iff\exists x[x\geq0\Rightarrow\forall y(y^2\neq x)]\]
 one year ago
 one year ago
\[\neg[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]]\iff\exists x[x\geq0\Rightarrow\forall y(y^2\neq x)]\]
 one year ago
 one year ago

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UnkleRhaukusBest ResponseYou've already chosen the best response.2
no wait , i see error
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.2
the negation of an implication
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
the negation of \(\to\) is \(\wedge\)
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
\[ \large \neg(p\to q)\equiv p\wedge\neg q \]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.2
\[\exists x[x<0\wedge\forall y(y^2\neq x)]\]
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
Ya that makes more sense
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
hmmm you edited your question but its still incorrect
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.2
\[\neg\left[\forall x[x < 0 \Rightarrow\exists y (y^2 = x)]\right]\iff\exists x\left[x<0\land\forall y(y^2\neq x)\right]\]
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
Yes thats the answer
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.2
thanks to you both
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
not that I helped :P
 one year ago
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