PLEASE HELP!!!! URGENT!!!
Explain why the following statement is NOT true: "The day before a big election, a pre-election survey showed that Candidate A got 52%, and Candidate B got 48%. The margin of error is 3%. If nothing changes, Candidate A will win. "
Thanks! =)

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- anonymous

If the margin of error is 3%, then A could be as low as 52 -3 = 49%.
or as high as 52 +3 = 55%
and, also,
B could be as low as 48 -3 = 45%
or as high as 48 + 3 = 51%.

- anonymous

a=0.03 is really a small ratio, so we assume its nearly impossible for a point to locate in a<=0.03 that area, then we say A will win

- anonymous

So, it is possible that A is at 49% and B is at 51%,
so B could be winning if nothing changes.

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- anonymous

You can show this by finding the highest and lowest the percents could be using the 3% margin of error. For example, if you calculate the president with the 48% as the highest it can be and the lowest it can be using the 3% and this percent is still less than the other president when the same process is applied to that president, the statement is true.

- anonymous

Wow! Thanks SO much, everybody! :) I so appreciate this!

- anonymous

I hope you were able to find the answer. :)

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