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Divide: 5x^2-20x/4x-9 divide by x-4/4x-9

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\[\frac{5x^2-20x}{4x-9} \div \frac{ x-4}{4x-9 }\]Change the divide sign: \[\frac{5x^2-20x}{4x-9} \times \frac{ 4x-9}{x-4 }\]
Ok I get that part, then what?
factor a 5x out of the top and you get 5x(x-4)

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Other answers:

\[\frac{5x^2-20x}{\cancel{4x-9}} \times \frac{ \cancel{4x-9}}{x-4 }\]
Do you see something in the top and bottom that can cancel out before you do any factoring?
@saifoo.khan just illustrated my point
I was going to say 4x-9
Change sign, cancel out, what is the next step
factor out a common multiple would be the next step illustrated above
Ohhh I get it!
We got lucky with this problem and you can see another canceling out possibility

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