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Helenshouse

  • 3 years ago

Divide: 5x^2-20x/4x-9 divide by x-4/4x-9

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  1. saifoo.khan
    • 3 years ago
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    \[\frac{5x^2-20x}{4x-9} \div \frac{ x-4}{4x-9 }\]Change the divide sign: \[\frac{5x^2-20x}{4x-9} \times \frac{ 4x-9}{x-4 }\]

  2. Helenshouse
    • 3 years ago
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    Ok I get that part, then what?

  3. kmalone99
    • 3 years ago
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    factor a 5x out of the top and you get 5x(x-4)

  4. saifoo.khan
    • 3 years ago
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    \[\frac{5x^2-20x}{\cancel{4x-9}} \times \frac{ \cancel{4x-9}}{x-4 }\]

  5. ChmE
    • 3 years ago
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    Do you see something in the top and bottom that can cancel out before you do any factoring?

  6. ChmE
    • 3 years ago
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    @saifoo.khan just illustrated my point

  7. Helenshouse
    • 3 years ago
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    I was going to say 4x-9

  8. Helenshouse
    • 3 years ago
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    Change sign, cancel out, what is the next step

  9. saifoo.khan
    • 3 years ago
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    |dw:1350791060484:dw|

  10. ChmE
    • 3 years ago
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    factor out a common multiple would be the next step illustrated above

  11. Helenshouse
    • 3 years ago
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    Ohhh I get it!

  12. ChmE
    • 3 years ago
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    We got lucky with this problem and you can see another canceling out possibility

  13. Helenshouse
    • 3 years ago
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    yes

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