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sevenshaded
 2 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=0}^{\infty}n e ^{n ^{2}}\]

sevenshaded
 2 years ago
Best ResponseYou've already chosen the best response.0I keep getting a final answer of \[(1/2) e^{b ^{2}} + 1/2 e^{0^{2}}\]where b is going to infinity. I would think that would come out to infinity plus 1/2, which would be infinity and cause the whole thing to diverge. However, according to problem (d) on this study sheet I found, the answer converges. Something is wrong with my algebra. Help please? http://www.hillsdalesites.org/personal/dmurphy/Kclasses/math113/review2solns.pdf Actually, I think I just solved my own problem. Would it be 0 + 1/2 because the \[^{b ^{2}} \] moves e to the denominator and thus makes that part go to zero?
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