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namonminejasisyt
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Mar and Ros working together can both encode a maniscript in 6 hours. If mar requires 5 hours longer to do the encoding than ros..how many hours can each do the encoding alone?
it's all about problem solving.
 2 years ago
 2 years ago
namonminejasisyt Group Title
Mar and Ros working together can both encode a maniscript in 6 hours. If mar requires 5 hours longer to do the encoding than ros..how many hours can each do the encoding alone? it's all about problem solving.
 2 years ago
 2 years ago

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cinar Group TitleBest ResponseYou've already chosen the best response.0
1/a +1/b =1/6 a=b+6
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
wouldn't it be a=b+5 ?
 2 years ago

namonminejasisyt Group TitleBest ResponseYou've already chosen the best response.0
oh wait2. my bad, it's all about work problems. not word problems.
 2 years ago

namonminejasisyt Group TitleBest ResponseYou've already chosen the best response.0
the work formula is Q=RT
 2 years ago

namonminejasisyt Group TitleBest ResponseYou've already chosen the best response.0
Can you please give me the whole answer?
 2 years ago

cinar Group TitleBest ResponseYou've already chosen the best response.0
1/(b+5) +1/b=1/6
 2 years ago

namonminejasisyt Group TitleBest ResponseYou've already chosen the best response.0
okay thanks.
 2 years ago

amriju Group TitleBest ResponseYou've already chosen the best response.0
lets try simple algebra....mar( i hope she's pretty) takes 5 hours more than ros...now lets assume ros takes 'x' hours to do that crap alone...so mar takes x+5 hours..clearly. Now how much can ros do in one hour....she can encode(1/x) part...rite..? tAnd mar can do (1/x+5) part....now they r united...in one hour they together do ((1/x)+(1/x+5)) part.... now that much part in 1 hour...and the total work is ofcourse 1 part...so u use unitary method to find out the time taken in terms of x... and equate it with the accual time reqd thats 6 hours....find x..thats time for ros...the eqn is.."x^27x30=0 " and x=10..
 2 years ago

namonminejasisyt Group TitleBest ResponseYou've already chosen the best response.0
it's all about work problems. anyone give me the right answer? the whole correct answer with the formula on.
 2 years ago
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