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Mar and Ros working together can both encode a maniscript in 6 hours. If mar requires 5 hours longer to do the encoding than ros..how many hours can each do the encoding alone?
it's all about problem solving.
 one year ago
 one year ago
Mar and Ros working together can both encode a maniscript in 6 hours. If mar requires 5 hours longer to do the encoding than ros..how many hours can each do the encoding alone? it's all about problem solving.
 one year ago
 one year ago

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namonminejasisytBest ResponseYou've already chosen the best response.0
oh wait2. my bad, it's all about work problems. not word problems.
 one year ago

namonminejasisytBest ResponseYou've already chosen the best response.0
the work formula is Q=RT
 one year ago

namonminejasisytBest ResponseYou've already chosen the best response.0
Can you please give me the whole answer?
 one year ago

amrijuBest ResponseYou've already chosen the best response.0
lets try simple algebra....mar( i hope she's pretty) takes 5 hours more than ros...now lets assume ros takes 'x' hours to do that crap alone...so mar takes x+5 hours..clearly. Now how much can ros do in one hour....she can encode(1/x) part...rite..? tAnd mar can do (1/x+5) part....now they r united...in one hour they together do ((1/x)+(1/x+5)) part.... now that much part in 1 hour...and the total work is ofcourse 1 part...so u use unitary method to find out the time taken in terms of x... and equate it with the accual time reqd thats 6 hours....find x..thats time for ros...the eqn is.."x^27x30=0 " and x=10..
 one year ago

namonminejasisytBest ResponseYou've already chosen the best response.0
it's all about work problems. anyone give me the right answer? the whole correct answer with the formula on.
 one year ago
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