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|dw:1350805115720:dw|

|dw:1350805844589:dw|

Ignore me too. I just realized this probably requires calculus stuff I'm not familiar with. :P

Maybe this is an optimization problem or something?

yes sir,,i do..

im getting this
minimize : .09 r/2 [1 - \(\frac{sin\theta}{\theta}\) ]

ohh \(\theta \) is also constant here as volume is fixed, hang on..

Sorry @shubhamsrg I had to go away for a second but am back now. OK give me a second.

take your time sir! :)

http://mathworld.wolfram.com/Quarter-TankProblem.html

\[ \huge {\pi r^2 \over {2\pi \over \theta}} - {1\over2}rr \sin \theta = 0.09 \pi r^2 \]

The cylinder can be tilted any way or it is tilted in following way|dw:1350825580056:dw|

res on its side right,,i'd assume the one in your figure..

Then, I dont think its a calculas problem.

@mukushla ? :/

|dw:1350914228619:dw|

Isnt x=9 given???

And we have to prove |dw:1350915430127:dw|

Did u solve theta and pluged in its value ???