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UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1im good at eigen values

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1ohh finally.. ok i have a question.. i know how to solve.. just for oncae type of case i dont know how to solve.. i will post up the question [ 6 5 2 2 0 8 5 4 0 ] this is the matrix.

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0do you have your eigen values ?

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0If I am not getting it wrong, then I think we will do like this to find eigen values : A  IX = 0 Something like that... No knowledge... @UnkleRhaukus please help your friend (me)...

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0Where is lambda?? Oh my God...

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[\textbf Ax=\lambda x\]\[(\textbf A\lambda \textbf I)x=0\]

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0Oh yeah.... I forgot all the things... One day, I found a page thrown by someone on the road, I read that.. There on the page, it was shown how to find Eigen values but the question was not complete.. And I have forgot that too...

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1i have found lammida.. and its 2

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1there is repeated roots?

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1yes all 3 values of lamida are 2

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0I try to find eigen value now... You can carry on @UnkleRhaukus

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[\textbf A=\left[\begin{array}{ccc}6&5&2\\2&0&8\\5&4&0\end{array}\right]\]\[x=\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]\]\[\lambda=2\] \[\left[\begin{array}{ccc}6&5&2\\2&0&8\\5&4&0\end{array}\right]\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]=2\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[\left[\begin{array}{ccc}62&5&2\\2&02&8\\5&4&02\end{array}\right]\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]=\left[\begin{array}{ccc} 0\\0\\0\end{array}\right]\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1you have three simultaneous equations

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1ok so i have to just solve simultaneously to get first eigen vector?

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1something like that, i always go confused when it comes to eigenvectors

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1i think first eigen vector is x1= = 2 x2 = 2 x3 = 1

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0\[4x_1 + 5x_2 + 2x_3 = 0\] \[2x_1 2x_2  8x_3 = 0\] \[5x_1 + 4x_2  2x_3 = 0\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1@nubeer , that certainly solves the three equations, how did you get there?

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1i have found x1 and x2 in terms of x3 while using subsitution method.

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1ok thanks guys.. i think i have done it... thank you very much espacially @UnkleRhaukus :)
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