nubeer
  • nubeer
Anyone good at Eigen Vectors.
Mathematics
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
UnkleRhaukus
  • UnkleRhaukus
im good at eigen values
nubeer
  • nubeer
ohh finally.. ok i have a question.. i know how to solve.. just for oncae type of case i dont know how to solve.. i will post up the question [ 6 5 2 2 0 -8 5 4 0 ] this is the matrix.
zzr0ck3r
  • zzr0ck3r
do you have your eigen values ?

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nubeer
  • nubeer
yes i have .. its 2
anonymous
  • anonymous
If I am not getting it wrong, then I think we will do like this to find eigen values : A - IX = 0 Something like that... No knowledge... @UnkleRhaukus please help your friend (me)...
anonymous
  • anonymous
Where is lambda?? Oh my God...
UnkleRhaukus
  • UnkleRhaukus
\[\textbf Ax=\lambda x\]\[(\textbf A-\lambda \textbf I)x=0\]
anonymous
  • anonymous
Oh yeah.... I forgot all the things... One day, I found a page thrown by someone on the road, I read that.. There on the page, it was shown how to find Eigen values but the question was not complete.. And I have forgot that too...
nubeer
  • nubeer
i have found lammida.. and its 2
UnkleRhaukus
  • UnkleRhaukus
there is repeated roots?
nubeer
  • nubeer
yes all 3 values of lamida are 2
anonymous
  • anonymous
I try to find eigen value now... You can carry on @UnkleRhaukus
UnkleRhaukus
  • UnkleRhaukus
\[\textbf A=\left[\begin{array}{ccc}6&5&2\\2&0&-8\\5&4&0\end{array}\right]\]\[x=\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]\]\[\lambda=2\] \[\left[\begin{array}{ccc}6&5&2\\2&0&-8\\5&4&0\end{array}\right]\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]=2\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]\]
UnkleRhaukus
  • UnkleRhaukus
\[\left[\begin{array}{ccc}6-2&5&2\\2&0-2&-8\\5&4&0-2\end{array}\right]\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]=\left[\begin{array}{ccc} 0\\0\\0\end{array}\right]\]
nubeer
  • nubeer
ok.. got this far...
UnkleRhaukus
  • UnkleRhaukus
you have three simultaneous equations
nubeer
  • nubeer
ok so i have to just solve simultaneously to get first eigen vector?
UnkleRhaukus
  • UnkleRhaukus
something like that, i always go confused when it comes to eigenvectors
nubeer
  • nubeer
i think first eigen vector is x1= = 2 x2 = -2 x3 = 1
anonymous
  • anonymous
\[4x_1 + 5x_2 + 2x_3 = 0\] \[2x_1 -2x_2 - 8x_3 = 0\] \[5x_1 + 4x_2 - 2x_3 = 0\]
UnkleRhaukus
  • UnkleRhaukus
@nubeer , that certainly solves the three equations, how did you get there?
nubeer
  • nubeer
i have found x1 and x2 in terms of x3 while using subsitution method.
nubeer
  • nubeer
ok thanks guys.. i think i have done it... thank you very much espacially @UnkleRhaukus :)

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