Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

nubeer

Anyone good at Eigen Vectors.

  • one year ago
  • one year ago

  • This Question is Closed
  1. UnkleRhaukus
    Best Response
    You've already chosen the best response.
    Medals 1

    im good at eigen values

    • one year ago
  2. nubeer
    Best Response
    You've already chosen the best response.
    Medals 1

    ohh finally.. ok i have a question.. i know how to solve.. just for oncae type of case i dont know how to solve.. i will post up the question [ 6 5 2 2 0 -8 5 4 0 ] this is the matrix.

    • one year ago
  3. zzr0ck3r
    Best Response
    You've already chosen the best response.
    Medals 0

    do you have your eigen values ?

    • one year ago
  4. nubeer
    Best Response
    You've already chosen the best response.
    Medals 1

    yes i have .. its 2

    • one year ago
  5. waterineyes
    Best Response
    You've already chosen the best response.
    Medals 0

    If I am not getting it wrong, then I think we will do like this to find eigen values : A - IX = 0 Something like that... No knowledge... @UnkleRhaukus please help your friend (me)...

    • one year ago
  6. waterineyes
    Best Response
    You've already chosen the best response.
    Medals 0

    Where is lambda?? Oh my God...

    • one year ago
  7. UnkleRhaukus
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\textbf Ax=\lambda x\]\[(\textbf A-\lambda \textbf I)x=0\]

    • one year ago
  8. waterineyes
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh yeah.... I forgot all the things... One day, I found a page thrown by someone on the road, I read that.. There on the page, it was shown how to find Eigen values but the question was not complete.. And I have forgot that too...

    • one year ago
  9. nubeer
    Best Response
    You've already chosen the best response.
    Medals 1

    i have found lammida.. and its 2

    • one year ago
  10. UnkleRhaukus
    Best Response
    You've already chosen the best response.
    Medals 1

    there is repeated roots?

    • one year ago
  11. nubeer
    Best Response
    You've already chosen the best response.
    Medals 1

    yes all 3 values of lamida are 2

    • one year ago
  12. waterineyes
    Best Response
    You've already chosen the best response.
    Medals 0

    I try to find eigen value now... You can carry on @UnkleRhaukus

    • one year ago
  13. UnkleRhaukus
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\textbf A=\left[\begin{array}{ccc}6&5&2\\2&0&-8\\5&4&0\end{array}\right]\]\[x=\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]\]\[\lambda=2\] \[\left[\begin{array}{ccc}6&5&2\\2&0&-8\\5&4&0\end{array}\right]\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]=2\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]\]

    • one year ago
  14. UnkleRhaukus
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\left[\begin{array}{ccc}6-2&5&2\\2&0-2&-8\\5&4&0-2\end{array}\right]\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]=\left[\begin{array}{ccc} 0\\0\\0\end{array}\right]\]

    • one year ago
  15. nubeer
    Best Response
    You've already chosen the best response.
    Medals 1

    ok.. got this far...

    • one year ago
  16. UnkleRhaukus
    Best Response
    You've already chosen the best response.
    Medals 1

    you have three simultaneous equations

    • one year ago
  17. nubeer
    Best Response
    You've already chosen the best response.
    Medals 1

    ok so i have to just solve simultaneously to get first eigen vector?

    • one year ago
  18. UnkleRhaukus
    Best Response
    You've already chosen the best response.
    Medals 1

    something like that, i always go confused when it comes to eigenvectors

    • one year ago
  19. nubeer
    Best Response
    You've already chosen the best response.
    Medals 1

    i think first eigen vector is x1= = 2 x2 = -2 x3 = 1

    • one year ago
  20. waterineyes
    Best Response
    You've already chosen the best response.
    Medals 0

    \[4x_1 + 5x_2 + 2x_3 = 0\] \[2x_1 -2x_2 - 8x_3 = 0\] \[5x_1 + 4x_2 - 2x_3 = 0\]

    • one year ago
  21. UnkleRhaukus
    Best Response
    You've already chosen the best response.
    Medals 1

    @nubeer , that certainly solves the three equations, how did you get there?

    • one year ago
  22. nubeer
    Best Response
    You've already chosen the best response.
    Medals 1

    i have found x1 and x2 in terms of x3 while using subsitution method.

    • one year ago
  23. nubeer
    Best Response
    You've already chosen the best response.
    Medals 1

    ok thanks guys.. i think i have done it... thank you very much espacially @UnkleRhaukus :)

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.