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UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
im good at eigen values
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
ohh finally.. ok i have a question.. i know how to solve.. just for oncae type of case i dont know how to solve.. i will post up the question [ 6 5 2 2 0 8 5 4 0 ] this is the matrix.
 2 years ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.0
do you have your eigen values ?
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
yes i have .. its 2
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
If I am not getting it wrong, then I think we will do like this to find eigen values : A  IX = 0 Something like that... No knowledge... @UnkleRhaukus please help your friend (me)...
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
Where is lambda?? Oh my God...
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
\[\textbf Ax=\lambda x\]\[(\textbf A\lambda \textbf I)x=0\]
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
Oh yeah.... I forgot all the things... One day, I found a page thrown by someone on the road, I read that.. There on the page, it was shown how to find Eigen values but the question was not complete.. And I have forgot that too...
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
i have found lammida.. and its 2
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
there is repeated roots?
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
yes all 3 values of lamida are 2
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
I try to find eigen value now... You can carry on @UnkleRhaukus
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
\[\textbf A=\left[\begin{array}{ccc}6&5&2\\2&0&8\\5&4&0\end{array}\right]\]\[x=\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]\]\[\lambda=2\] \[\left[\begin{array}{ccc}6&5&2\\2&0&8\\5&4&0\end{array}\right]\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]=2\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]\]
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
\[\left[\begin{array}{ccc}62&5&2\\2&02&8\\5&4&02\end{array}\right]\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]=\left[\begin{array}{ccc} 0\\0\\0\end{array}\right]\]
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
ok.. got this far...
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
you have three simultaneous equations
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
ok so i have to just solve simultaneously to get first eigen vector?
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
something like that, i always go confused when it comes to eigenvectors
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
i think first eigen vector is x1= = 2 x2 = 2 x3 = 1
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
\[4x_1 + 5x_2 + 2x_3 = 0\] \[2x_1 2x_2  8x_3 = 0\] \[5x_1 + 4x_2  2x_3 = 0\]
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
@nubeer , that certainly solves the three equations, how did you get there?
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
i have found x1 and x2 in terms of x3 while using subsitution method.
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
ok thanks guys.. i think i have done it... thank you very much espacially @UnkleRhaukus :)
 2 years ago
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