A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1im good at eigen values

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1ohh finally.. ok i have a question.. i know how to solve.. just for oncae type of case i dont know how to solve.. i will post up the question [ 6 5 2 2 0 8 5 4 0 ] this is the matrix.

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0do you have your eigen values ?

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0If I am not getting it wrong, then I think we will do like this to find eigen values : A  IX = 0 Something like that... No knowledge... @UnkleRhaukus please help your friend (me)...

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0Where is lambda?? Oh my God...

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[\textbf Ax=\lambda x\]\[(\textbf A\lambda \textbf I)x=0\]

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0Oh yeah.... I forgot all the things... One day, I found a page thrown by someone on the road, I read that.. There on the page, it was shown how to find Eigen values but the question was not complete.. And I have forgot that too...

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1i have found lammida.. and its 2

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1there is repeated roots?

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1yes all 3 values of lamida are 2

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0I try to find eigen value now... You can carry on @UnkleRhaukus

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[\textbf A=\left[\begin{array}{ccc}6&5&2\\2&0&8\\5&4&0\end{array}\right]\]\[x=\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]\]\[\lambda=2\] \[\left[\begin{array}{ccc}6&5&2\\2&0&8\\5&4&0\end{array}\right]\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]=2\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[\left[\begin{array}{ccc}62&5&2\\2&02&8\\5&4&02\end{array}\right]\left[\begin{array}{ccc} x_1\\x_2\\x_3\end{array}\right]=\left[\begin{array}{ccc} 0\\0\\0\end{array}\right]\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1you have three simultaneous equations

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1ok so i have to just solve simultaneously to get first eigen vector?

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1something like that, i always go confused when it comes to eigenvectors

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1i think first eigen vector is x1= = 2 x2 = 2 x3 = 1

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0\[4x_1 + 5x_2 + 2x_3 = 0\] \[2x_1 2x_2  8x_3 = 0\] \[5x_1 + 4x_2  2x_3 = 0\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1@nubeer , that certainly solves the three equations, how did you get there?

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1i have found x1 and x2 in terms of x3 while using subsitution method.

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.1ok thanks guys.. i think i have done it... thank you very much espacially @UnkleRhaukus :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.