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im good at eigen values

do you have your eigen values ?

yes i have .. its 2

Where is lambda??
Oh my God...

\[\textbf Ax=\lambda x\]\[(\textbf A-\lambda \textbf I)x=0\]

i have found lammida.. and its 2

there is repeated roots?

yes all 3 values of lamida are 2

I try to find eigen value now...
You can carry on @UnkleRhaukus

ok.. got this far...

you have three simultaneous equations

ok so i have to just solve simultaneously to get first eigen vector?

something like that, i always go confused when it comes to eigenvectors

i think first eigen vector is
x1= = 2
x2 = -2
x3 = 1

\[4x_1 + 5x_2 + 2x_3 = 0\]
\[2x_1 -2x_2 - 8x_3 = 0\]
\[5x_1 + 4x_2 - 2x_3 = 0\]

@nubeer , that certainly solves the three equations, how did you get there?

i have found x1 and x2 in terms of x3 while using subsitution method.

ok thanks guys.. i think i have done it... thank you very much espacially @UnkleRhaukus :)