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klimenkov
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What about this? \[\int{\frac{\sin x+\cos x}{\cos x  \sin x}}dx\]
 2 years ago
 2 years ago
klimenkov Group Title
What about this? \[\int{\frac{\sin x+\cos x}{\cos x  \sin x}}dx\]
 2 years ago
 2 years ago

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SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.0
multiply both sides by cos x + sin x
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.0
You will get like this : \[\large{\frac{1 + 2cosx.sinx}{cos^2xsin^2x}}\]
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.0
Simplify n integrate.
 2 years ago

amriju Group TitleBest ResponseYou've already chosen the best response.0
multiply num and den. by cosx + sinx...and solve for sec2x+tan2X
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.4
well, do u know this standard identity \(\huge \int \frac{f'(x)}{f(x)}dx=lnf(x)+c\) no need to multiply or divide anything.....
 2 years ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.0
Very nice @hartnn. Your way is the quickest.
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.0
@hartnn so it will be : \(\large{ln (\cos x  \sin x)+C}\)
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.0
oh sorry there is mod instead of brackets
 2 years ago

amriju Group TitleBest ResponseYou've already chosen the best response.0
thats wrong...u should nt have played with our prestige in public...:P @hartnn
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.4
with a negative sign
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.0
why ve ?
 2 years ago

amriju Group TitleBest ResponseYou've already chosen the best response.0
yeah..ofcrse
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.4
d/dx(cos xsin x) = sin xcos x
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.0
Oh ok got it :)
 2 years ago
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