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SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.0multiply both sides by cos x + sin x

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.0You will get like this : \[\large{\frac{1 + 2cosx.sinx}{cos^2xsin^2x}}\]

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.0Simplify n integrate.

amriju
 2 years ago
Best ResponseYou've already chosen the best response.0multiply num and den. by cosx + sinx...and solve for sec2x+tan2X

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4well, do u know this standard identity \(\huge \int \frac{f'(x)}{f(x)}dx=lnf(x)+c\) no need to multiply or divide anything.....

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.0Very nice @hartnn. Your way is the quickest.

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.0@hartnn so it will be : \(\large{ln (\cos x  \sin x)+C}\)

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.0oh sorry there is mod instead of brackets

amriju
 2 years ago
Best ResponseYou've already chosen the best response.0thats wrong...u should nt have played with our prestige in public...:P @hartnn

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4d/dx(cos xsin x) = sin xcos x

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.0Oh ok got it :)
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