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1) a=b 2) ab=a^2 3) abb^2=a^2b^2 4) b(ab)=(a+b)(ab) 5) b= a+b
Reminder the first step where b = 2b So,
1=2.
In this case in my opinion the wrong step is that in the third, because you can´t subtract b^2 from both sides.
 one year ago
 one year ago
1) a=b 2) ab=a^2 3) abb^2=a^2b^2 4) b(ab)=(a+b)(ab) 5) b= a+b Reminder the first step where b = 2b So, 1=2. In this case in my opinion the wrong step is that in the third, because you can´t subtract b^2 from both sides.
 one year ago
 one year ago

This Question is Closed

ParthKohliBest ResponseYou've already chosen the best response.2
Transition from step 45 is wrong. Guess why!
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
Tell me ParthKohli.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Division by zero. Period.
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
Write stepbystep. plz.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
\[\rm b(a  b) = (a + b)(a  b)\]Since (a  b) = 0,\[\rm 0b = 0(a + b)\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
But what this thing shows is that it's divided both sides by 0.
 one year ago
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