anonymous
  • anonymous
1) a=b 2) ab=a^2 3) ab-b^2=a^2-b^2 4) b(a-b)=(a+b)(a-b) 5) b= a+b Reminder the first step where b = 2b So, 1=2. In this case in my opinion the wrong step is that in the third, because you can´t subtract -b^2 from both sides.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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ParthKohli
  • ParthKohli
lol why not?
ParthKohli
  • ParthKohli
Transition from step 4-5 is wrong. Guess why!
anonymous
  • anonymous
Tell me ParthKohli.

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ParthKohli
  • ParthKohli
Division by zero. Period.
anonymous
  • anonymous
Write step-by-step. plz.
ParthKohli
  • ParthKohli
\[\rm b(a - b) = (a + b)(a - b)\]Since (a - b) = 0,\[\rm 0b = 0(a + b)\]
ParthKohli
  • ParthKohli
But what this thing shows is that it's divided both sides by 0.
anonymous
  • anonymous
thanks

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