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viniterranova

1) a=b 2) ab=a^2 3) ab-b^2=a^2-b^2 4) b(a-b)=(a+b)(a-b) 5) b= a+b Reminder the first step where b = 2b So, 1=2. In this case in my opinion the wrong step is that in the third, because you can´t subtract -b^2 from both sides.

  • one year ago
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  1. ParthKohli
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    lol why not?

    • one year ago
  2. ParthKohli
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    Transition from step 4-5 is wrong. Guess why!

    • one year ago
  3. viniterranova
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    Tell me ParthKohli.

    • one year ago
  4. ParthKohli
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    Division by zero. Period.

    • one year ago
  5. viniterranova
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    Write step-by-step. plz.

    • one year ago
  6. ParthKohli
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    \[\rm b(a - b) = (a + b)(a - b)\]Since (a - b) = 0,\[\rm 0b = 0(a + b)\]

    • one year ago
  7. ParthKohli
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    But what this thing shows is that it's divided both sides by 0.

    • one year ago
  8. viniterranova
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    thanks

    • one year ago
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