lgbasallote
  • lgbasallote
Rationalize: \[\huge \frac{\sqrt{4+h} - 2}h\]
Algebra
chestercat
  • chestercat
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anonymous
  • anonymous
\[\frac{ 4+h-4 }{ h(\sqrt{4+h}+2) }=\frac{ 1 }{\sqrt{4+h}+2 }\] nomarlly limit question
anonymous
  • anonymous
we multiplied by\[\sqrt{4+h}+2\] both num and denominator
lgbasallote
  • lgbasallote
hmmm...isn't the point of rationalization to remove radicals from the denominator?

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swissgirl
  • swissgirl
Well then there were no radicals in the denominator
swissgirl
  • swissgirl
So u wld keep it the way it is
lgbasallote
  • lgbasallote
really?
anonymous
  • anonymous
imagine if this question was\[\lim_{h \rightarrow 0}\frac{ \sqrt{4+h}-2 }{ h }\]
lgbasallote
  • lgbasallote
??
anonymous
  • anonymous
you cant just plug h=0 here but in the rationalised one
swissgirl
  • swissgirl
Ohh that is cool :P
lgbasallote
  • lgbasallote
limits in an algebra question? that's morbid.....
ParthKohli
  • ParthKohli
Rationalizing means to remove the radical from the place it is in...
swissgirl
  • swissgirl
hmmm well u can be asked to rationalize the numerator too
lgbasallote
  • lgbasallote
now im confused with the contradictions...
swissgirl
  • swissgirl
What are the contradictions?
lgbasallote
  • lgbasallote
@swissgirl said don't change...now she says change
swissgirl
  • swissgirl
Just use ur own brain -_-
swissgirl
  • swissgirl
lol
lgbasallote
  • lgbasallote
someone's wrong here....wonder who
ParthKohli
  • ParthKohli
If they ask you to rationalize the fraction, you do these: 1) If the radical is in the denominator — remove it from the denominator. Do not care about the numerator. 2) If the radical is in the numerator — remove it from the numerator. Do not care about the denominator.
anonymous
  • anonymous
\[\frac{ 1 }{ \sqrt{2} }=\frac{ \sqrt{2} }{ 2 }\]
anonymous
  • anonymous
rationalised
lgbasallote
  • lgbasallote
i know what happens if it's in the denominator
swissgirl
  • swissgirl
trust me lgba knows how to rationalize a numerator or denomanator
lgbasallote
  • lgbasallote
the question is if it's in the numerator
ParthKohli
  • ParthKohli
See how you can't remove the radical from both numerator and denominator?
ParthKohli
  • ParthKohli
Yes, so move it to the denominator. Do not care about the denominator.
lgbasallote
  • lgbasallote
my question is not how to rationalize @swissgirl but if it's suppose to be rationalized
ParthKohli
  • ParthKohli
You can rationalize it, but mathematicians always love if the radical is in the numerator.
lgbasallote
  • lgbasallote
because what i know is that if it's in the numerator, then it's okay
ParthKohli
  • ParthKohli
It's better to put radicals in the numerator rather than the denominator.
lgbasallote
  • lgbasallote
so why put in denominator then?
anonymous
  • anonymous
\[\frac{ \sqrt{2} }{ 2 }=\frac{ 1 }{ \sqrt{2} }\] these is also called rationalising sometimes it is convinient to write in the dinominatpr eg in the case of a limit
swissgirl
  • swissgirl
Well what i have always learnt was that rationalization=denominator but I have gone online and seen that some do rationalize the numerator too so it all depends what course you are taking and what you see in your the textbook
ParthKohli
  • ParthKohli
Yup, I saw that you could rationalize the numerator too though it's rare.
lgbasallote
  • lgbasallote
when i went online, all i saw were unreliable sources on rationalizing numerators
swissgirl
  • swissgirl
http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut41_rationalize.htm
ParthKohli
  • ParthKohli
Never rationalize the numerator unless given a question to perform.
swissgirl
  • swissgirl
http://tutorial.math.lamar.edu/Extras/AlgebraTrigReview/Rationalizing.aspx
lgbasallote
  • lgbasallote
\[\lim_{x \rightarrow 0} \sqrt x\]seems better than \[\lim_{x \rightarrow 0} \frac 1{\sqrt x}\] @Jonask
swissgirl
  • swissgirl
These are both reliable sources
lgbasallote
  • lgbasallote
hmm
anonymous
  • anonymous
how ever if you where asked to do the same function using the first prinsiple you will need to rationalise
lgbasallote
  • lgbasallote
the links win. can't argue with that.
anonymous
  • anonymous
\[\frac{ \sqrt{x+h}-\sqrt{x} }{ h }\]ration. \[\frac{ 1 }{ \sqrt{x+h}+\sqrt{x} }\]
lgbasallote
  • lgbasallote
square roots in denominators really look weird...

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