Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Rationalize: \[\huge \frac{\sqrt{4+h} - 2}h\]

Algebra
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

\[\frac{ 4+h-4 }{ h(\sqrt{4+h}+2) }=\frac{ 1 }{\sqrt{4+h}+2 }\] nomarlly limit question
we multiplied by\[\sqrt{4+h}+2\] both num and denominator
hmmm...isn't the point of rationalization to remove radicals from the denominator?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Well then there were no radicals in the denominator
So u wld keep it the way it is
really?
imagine if this question was\[\lim_{h \rightarrow 0}\frac{ \sqrt{4+h}-2 }{ h }\]
??
you cant just plug h=0 here but in the rationalised one
Ohh that is cool :P
limits in an algebra question? that's morbid.....
Rationalizing means to remove the radical from the place it is in...
hmmm well u can be asked to rationalize the numerator too
now im confused with the contradictions...
What are the contradictions?
@swissgirl said don't change...now she says change
Just use ur own brain -_-
lol
someone's wrong here....wonder who
If they ask you to rationalize the fraction, you do these: 1) If the radical is in the denominator — remove it from the denominator. Do not care about the numerator. 2) If the radical is in the numerator — remove it from the numerator. Do not care about the denominator.
\[\frac{ 1 }{ \sqrt{2} }=\frac{ \sqrt{2} }{ 2 }\]
rationalised
i know what happens if it's in the denominator
trust me lgba knows how to rationalize a numerator or denomanator
the question is if it's in the numerator
See how you can't remove the radical from both numerator and denominator?
Yes, so move it to the denominator. Do not care about the denominator.
my question is not how to rationalize @swissgirl but if it's suppose to be rationalized
You can rationalize it, but mathematicians always love if the radical is in the numerator.
because what i know is that if it's in the numerator, then it's okay
It's better to put radicals in the numerator rather than the denominator.
so why put in denominator then?
\[\frac{ \sqrt{2} }{ 2 }=\frac{ 1 }{ \sqrt{2} }\] these is also called rationalising sometimes it is convinient to write in the dinominatpr eg in the case of a limit
Well what i have always learnt was that rationalization=denominator but I have gone online and seen that some do rationalize the numerator too so it all depends what course you are taking and what you see in your the textbook
Yup, I saw that you could rationalize the numerator too though it's rare.
when i went online, all i saw were unreliable sources on rationalizing numerators
http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut41_rationalize.htm
Never rationalize the numerator unless given a question to perform.
http://tutorial.math.lamar.edu/Extras/AlgebraTrigReview/Rationalizing.aspx
\[\lim_{x \rightarrow 0} \sqrt x\]seems better than \[\lim_{x \rightarrow 0} \frac 1{\sqrt x}\] @Jonask
These are both reliable sources
hmm
how ever if you where asked to do the same function using the first prinsiple you will need to rationalise
the links win. can't argue with that.
\[\frac{ \sqrt{x+h}-\sqrt{x} }{ h }\]ration. \[\frac{ 1 }{ \sqrt{x+h}+\sqrt{x} }\]
square roots in denominators really look weird...

Not the answer you are looking for?

Search for more explanations.

Ask your own question