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JonaskBest ResponseYou've already chosen the best response.2
\[\frac{ 4+h4 }{ h(\sqrt{4+h}+2) }=\frac{ 1 }{\sqrt{4+h}+2 }\] nomarlly limit question
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
we multiplied by\[\sqrt{4+h}+2\] both num and denominator
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
hmmm...isn't the point of rationalization to remove radicals from the denominator?
 one year ago

swissgirlBest ResponseYou've already chosen the best response.1
Well then there were no radicals in the denominator
 one year ago

swissgirlBest ResponseYou've already chosen the best response.1
So u wld keep it the way it is
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
imagine if this question was\[\lim_{h \rightarrow 0}\frac{ \sqrt{4+h}2 }{ h }\]
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
you cant just plug h=0 here but in the rationalised one
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
limits in an algebra question? that's morbid.....
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Rationalizing means to remove the radical from the place it is in...
 one year ago

swissgirlBest ResponseYou've already chosen the best response.1
hmmm well u can be asked to rationalize the numerator too
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
now im confused with the contradictions...
 one year ago

swissgirlBest ResponseYou've already chosen the best response.1
What are the contradictions?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
@swissgirl said don't change...now she says change
 one year ago

swissgirlBest ResponseYou've already chosen the best response.1
Just use ur own brain _
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
someone's wrong here....wonder who
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
If they ask you to rationalize the fraction, you do these: 1) If the radical is in the denominator — remove it from the denominator. Do not care about the numerator. 2) If the radical is in the numerator — remove it from the numerator. Do not care about the denominator.
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
\[\frac{ 1 }{ \sqrt{2} }=\frac{ \sqrt{2} }{ 2 }\]
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
i know what happens if it's in the denominator
 one year ago

swissgirlBest ResponseYou've already chosen the best response.1
trust me lgba knows how to rationalize a numerator or denomanator
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
the question is if it's in the numerator
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
See how you can't remove the radical from both numerator and denominator?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Yes, so move it to the denominator. Do not care about the denominator.
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
my question is not how to rationalize @swissgirl but if it's suppose to be rationalized
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
You can rationalize it, but mathematicians always love if the radical is in the numerator.
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
because what i know is that if it's in the numerator, then it's okay
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
It's better to put radicals in the numerator rather than the denominator.
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
so why put in denominator then?
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
\[\frac{ \sqrt{2} }{ 2 }=\frac{ 1 }{ \sqrt{2} }\] these is also called rationalising sometimes it is convinient to write in the dinominatpr eg in the case of a limit
 one year ago

swissgirlBest ResponseYou've already chosen the best response.1
Well what i have always learnt was that rationalization=denominator but I have gone online and seen that some do rationalize the numerator too so it all depends what course you are taking and what you see in your the textbook
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Yup, I saw that you could rationalize the numerator too though it's rare.
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
when i went online, all i saw were unreliable sources on rationalizing numerators
 one year ago

swissgirlBest ResponseYou've already chosen the best response.1
http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut41_rationalize.htm
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Never rationalize the numerator unless given a question to perform.
 one year ago

swissgirlBest ResponseYou've already chosen the best response.1
http://tutorial.math.lamar.edu/Extras/AlgebraTrigReview/Rationalizing.aspx
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
\[\lim_{x \rightarrow 0} \sqrt x\]seems better than \[\lim_{x \rightarrow 0} \frac 1{\sqrt x}\] @Jonask
 one year ago

swissgirlBest ResponseYou've already chosen the best response.1
These are both reliable sources
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
how ever if you where asked to do the same function using the first prinsiple you will need to rationalise
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
the links win. can't argue with that.
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
\[\frac{ \sqrt{x+h}\sqrt{x} }{ h }\]ration. \[\frac{ 1 }{ \sqrt{x+h}+\sqrt{x} }\]
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
square roots in denominators really look weird...
 one year ago
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