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anonymous
 3 years ago
Rationalize:
\[\huge \frac{\sqrt{4+h}  2}h\]
anonymous
 3 years ago
Rationalize: \[\huge \frac{\sqrt{4+h}  2}h\]

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4+h4 }{ h(\sqrt{4+h}+2) }=\frac{ 1 }{\sqrt{4+h}+2 }\] nomarlly limit question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we multiplied by\[\sqrt{4+h}+2\] both num and denominator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmmm...isn't the point of rationalization to remove radicals from the denominator?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well then there were no radicals in the denominator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So u wld keep it the way it is

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0imagine if this question was\[\lim_{h \rightarrow 0}\frac{ \sqrt{4+h}2 }{ h }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you cant just plug h=0 here but in the rationalised one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0limits in an algebra question? that's morbid.....

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0Rationalizing means to remove the radical from the place it is in...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmmm well u can be asked to rationalize the numerator too

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now im confused with the contradictions...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What are the contradictions?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@swissgirl said don't change...now she says change

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Just use ur own brain _

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0someone's wrong here....wonder who

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0If they ask you to rationalize the fraction, you do these: 1) If the radical is in the denominator — remove it from the denominator. Do not care about the numerator. 2) If the radical is in the numerator — remove it from the numerator. Do not care about the denominator.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ \sqrt{2} }=\frac{ \sqrt{2} }{ 2 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know what happens if it's in the denominator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0trust me lgba knows how to rationalize a numerator or denomanator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the question is if it's in the numerator

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0See how you can't remove the radical from both numerator and denominator?

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, so move it to the denominator. Do not care about the denominator.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my question is not how to rationalize @swissgirl but if it's suppose to be rationalized

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0You can rationalize it, but mathematicians always love if the radical is in the numerator.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because what i know is that if it's in the numerator, then it's okay

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0It's better to put radicals in the numerator rather than the denominator.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so why put in denominator then?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sqrt{2} }{ 2 }=\frac{ 1 }{ \sqrt{2} }\] these is also called rationalising sometimes it is convinient to write in the dinominatpr eg in the case of a limit

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well what i have always learnt was that rationalization=denominator but I have gone online and seen that some do rationalize the numerator too so it all depends what course you are taking and what you see in your the textbook

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0Yup, I saw that you could rationalize the numerator too though it's rare.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when i went online, all i saw were unreliable sources on rationalizing numerators

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut41_rationalize.htm

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0Never rationalize the numerator unless given a question to perform.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://tutorial.math.lamar.edu/Extras/AlgebraTrigReview/Rationalizing.aspx

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0} \sqrt x\]seems better than \[\lim_{x \rightarrow 0} \frac 1{\sqrt x}\] @Jonask

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0These are both reliable sources

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how ever if you where asked to do the same function using the first prinsiple you will need to rationalise

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the links win. can't argue with that.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sqrt{x+h}\sqrt{x} }{ h }\]ration. \[\frac{ 1 }{ \sqrt{x+h}+\sqrt{x} }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0square roots in denominators really look weird...
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