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aiskarl

  • 3 years ago

find constan a and b

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  1. aiskarl
    • 3 years ago
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    \[\lim_{x \rightarrow 0} \frac{ \sqrt{ax+b}-1 }{ x }\] =1

  2. Stacey
    • 3 years ago
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    Have you tried rationalizing the fraction? (multilplying the both the numerator and denominator by [sqrt(ax+b) - 1] )

  3. Stacey
    • 3 years ago
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    It's not really rationalizing since it would put a radical in the denominator, but doing that often makes limits easier to solve.

  4. Jonask
    • 3 years ago
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    \[\frac{ ax+b-1 }{ x(\sqrt{ax+b}+1) }\]

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