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lgbasallote
Group Title
Find the domain:
\[h(x) = \sqrt{4x} + \sqrt{x^2  1}\]
 one year ago
 one year ago
lgbasallote Group Title
Find the domain: \[h(x) = \sqrt{4x} + \sqrt{x^2  1}\]
 one year ago
 one year ago

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lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i smell a race....
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Hint: you can't use positive numbers more than 4.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
^i wish you would have let me try first....
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
^@Jonask
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
^and then you did it again @Jonask
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
sorry,like you said its a race
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i hate races.....
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
Ok just try to see when each square root is negative
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
anyway....
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i suppose \(\sqrt{x^2  1}\) will have no restrictions?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
hmm oh yeah
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
didn't think of that
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
then \(\sqrt{4x}\) would be 4 above?
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
I would say greater than 4
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
@lgbasallote was that the question of 100 level???
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
greater than 4...4 above...same shiz
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Take Seperately and Connect it by union (U)
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
to be the best, one needs to master the basics @sauravshakya
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[f(x)=x^2,g(x)=\sqrt{1x}\] domain of\[gof,fog\] domain
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
just a question that i wont interupt you can try
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
Domain is just 1 and 0
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
g o f would be sqrt(1  x^2) it would only be nonnegative if 0 <= x <= 1
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so the domain is 0<=x<=1
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
for f(g(x))
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
f o g would be 1 x so all real numbers
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
\[Domain=(\infty,0) U (0,4]\]
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
0 isn't included in the domain since \(\sqrt{0^2  1} = \sqrt{1}\) and this is a real function.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Lol...@ParthKohli u see it is a open Bracket.....
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
"real" function?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
@Yahoo! I wasn't talking to you.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Yeah, which has all ranges as real numbers.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
oh.....Sorry...) @ParthKohli
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
now you confuse me...you're telling me they're wrong?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
swissgirl Best Response 1 Domain is just 1 and 0 that ^^
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
hmm seems one of the answers here is wrong then...wonder which
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Okay, let me ask you a question. Why didn't you include all real numbers in the domain? @lgbasallote
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
when didn't i?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
lgbasallote Best Response 0 i suppose sqrt(x62−1) will have no restrictions? swissgirl Best Response 1 yes x=0 lgbasallote Best Response 0 hmm oh yeah
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
0 is included in all real numbers.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
since when was \(\sqrt{1}\) real @ParthKohli ?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
You answered your own question @lgbasallote
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
....what exactly are you saying?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
ParthKohli 0 0 isn't included in the domain since sqrt(0^2  1) = sqrt(1) and this is a real function. <argument happens> ParthKohli 0 Okay, let me ask you a question. Why didn't you include all real numbers in the domain? @lgbasallote lgbasallote Best Response 0 i did lgbasallote Best Response 0 when didn't i? <some more convo> lgbasallote Best Response 0 since when was √−1 real @ParthKohli ?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
just state your point
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
You are contradicting yourself. First, you say that you have included all real numbers in the domain. Then, by "since when was √−1 real @ParthKohli ?," you mean that 0 is not in the domain.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
by the way 1) none of us said 0 is included in the domain (we were talking about restrictions) 2) sqrt 1 is not a real function
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[D_g=(\infty,1),D_f=\mathbb{R}\] \[fog=\left 1x \right\]\[gof=\sqrt{1x^2}\]
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
No, real function means that for all domains, the range will be real. We have to get a domain which keeps all ranges real.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
and your point is?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
That 0 is not in the domain.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
and isn't that what we said?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
You said that you included all real numbers in the domain. .
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
when???
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
we were talking about RESTRICTIONS
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
ParthKohli 0 Okay, let me ask you a question. Why didn't you include all real numbers in the domain? @lgbasallote lgbasallote i did 10 minutes ago lgbasallote Best Response 0 when didn't i?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
I was talking about the domain then.
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[D_{gof}=[1,1]\] \[Dfog=x \in (\infty,1]\]
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
you really tend to make things big when you misread, don;t you @ParthKohli
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
guys i think we can close the question i did not mean to create a big issue
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
it has been closed a long time ago @jonask
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
oh i dint notice,cos commentsn are still running
 one year ago
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