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i smell a race....

Hint: you can't use positive numbers more than 4.

^i wish you would have let me try first....

^and then you did it again @Jonask

sorry,like you said its a race

i hate races.....

Ok just try to see when each square root is negative

anyway....

i suppose \(\sqrt{x^2 - 1}\) will have no restrictions?

yes x=0

hmm oh yeah

didn't think of that

then \(\sqrt{4-x}\) would be 4 above?

I would say greater than 4

@lgbasallote was that the question of 100 level???

greater than 4...4 above...same shiz

Take Seperately and Connect it by union (U)

to be the best, one needs to master the basics @sauravshakya

\[f(x)=x^2,g(x)=\sqrt{1-x}\]
domain of\[gof,fog\]
domain

^?

just a question that i wont interupt you can try

Domain is just 1 and 0

g o f would be sqrt(1 - x^2)
it would only be non-negative if 0 <= x <= 1

so the domain is 0<=x<=1

for f(g(x))

f o g would be 1- x so all real numbers

\[Domain=(-\infty,0) U (0,4]\]

0 isn't included in the domain since \(\sqrt{0^2 - 1} = \sqrt{-1}\) and this is a real function.

Lol...@ParthKohli u see it is a open Bracket.....

"real" function?

@Yahoo! I wasn't talking to you.

Yeah, which has all ranges as real numbers.

oh.....Sorry...) @ParthKohli

now you confuse me...you're telling me they're wrong?

swissgirl Best Response 1
Domain is just 1 and 0
that ^^

hmm seems one of the answers here is wrong then...wonder which

Okay, let me ask you a question. Why didn't you include all real numbers in the domain? @lgbasallote

i did

when didn't i?

0 is included in all real numbers.

since when was \(\sqrt{-1}\) real @ParthKohli ?

You answered your own question @lgbasallote

....what exactly are you saying?

just state your point

\[D_g=(-\infty,1),D_f=\mathbb{R}\]
\[fog=\left| 1-x \right|\]\[gof=\sqrt{1-x^2}\]

^?

and your point is?

That 0 is not in the domain.

and isn't that what we said?

You said that you included all real numbers in the domain. -.-

when???

we were talking about RESTRICTIONS

I was talking about the domain then.

\[D_{gof}=[-1,1]\]
\[Dfog=x \in (-\infty,1]\]

you really tend to make things big when you misread, don;t you @ParthKohli

guys i think we can close the question i did not mean to create a big issue

it has been closed a long time ago @jonask

oh i dint notice,cos commentsn are still running