Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
lgbasallote
Group Title
Find the domain:
\[h(x) = \sqrt{4x} + \sqrt{x^2  1}\]
 2 years ago
 2 years ago
lgbasallote Group Title
Find the domain: \[h(x) = \sqrt{4x} + \sqrt{x^2  1}\]
 2 years ago
 2 years ago

This Question is Closed

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i smell a race....
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Hint: you can't use positive numbers more than 4.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
^i wish you would have let me try first....
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
^@Jonask
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
^and then you did it again @Jonask
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
sorry,like you said its a race
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i hate races.....
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
Ok just try to see when each square root is negative
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
anyway....
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i suppose \(\sqrt{x^2  1}\) will have no restrictions?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
hmm oh yeah
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
didn't think of that
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
then \(\sqrt{4x}\) would be 4 above?
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
I would say greater than 4
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
@lgbasallote was that the question of 100 level???
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
greater than 4...4 above...same shiz
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Take Seperately and Connect it by union (U)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
to be the best, one needs to master the basics @sauravshakya
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[f(x)=x^2,g(x)=\sqrt{1x}\] domain of\[gof,fog\] domain
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
just a question that i wont interupt you can try
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
Domain is just 1 and 0
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
g o f would be sqrt(1  x^2) it would only be nonnegative if 0 <= x <= 1
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so the domain is 0<=x<=1
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
for f(g(x))
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
f o g would be 1 x so all real numbers
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
\[Domain=(\infty,0) U (0,4]\]
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
0 isn't included in the domain since \(\sqrt{0^2  1} = \sqrt{1}\) and this is a real function.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Lol...@ParthKohli u see it is a open Bracket.....
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
"real" function?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
@Yahoo! I wasn't talking to you.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Yeah, which has all ranges as real numbers.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
oh.....Sorry...) @ParthKohli
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
now you confuse me...you're telling me they're wrong?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
swissgirl Best Response 1 Domain is just 1 and 0 that ^^
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
hmm seems one of the answers here is wrong then...wonder which
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Okay, let me ask you a question. Why didn't you include all real numbers in the domain? @lgbasallote
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
when didn't i?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
lgbasallote Best Response 0 i suppose sqrt(x62−1) will have no restrictions? swissgirl Best Response 1 yes x=0 lgbasallote Best Response 0 hmm oh yeah
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
0 is included in all real numbers.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
since when was \(\sqrt{1}\) real @ParthKohli ?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
You answered your own question @lgbasallote
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
....what exactly are you saying?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
ParthKohli 0 0 isn't included in the domain since sqrt(0^2  1) = sqrt(1) and this is a real function. <argument happens> ParthKohli 0 Okay, let me ask you a question. Why didn't you include all real numbers in the domain? @lgbasallote lgbasallote Best Response 0 i did lgbasallote Best Response 0 when didn't i? <some more convo> lgbasallote Best Response 0 since when was √−1 real @ParthKohli ?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
just state your point
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
You are contradicting yourself. First, you say that you have included all real numbers in the domain. Then, by "since when was √−1 real @ParthKohli ?," you mean that 0 is not in the domain.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
by the way 1) none of us said 0 is included in the domain (we were talking about restrictions) 2) sqrt 1 is not a real function
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[D_g=(\infty,1),D_f=\mathbb{R}\] \[fog=\left 1x \right\]\[gof=\sqrt{1x^2}\]
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
No, real function means that for all domains, the range will be real. We have to get a domain which keeps all ranges real.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
and your point is?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
That 0 is not in the domain.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
and isn't that what we said?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
You said that you included all real numbers in the domain. .
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
when???
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
we were talking about RESTRICTIONS
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
ParthKohli 0 Okay, let me ask you a question. Why didn't you include all real numbers in the domain? @lgbasallote lgbasallote i did 10 minutes ago lgbasallote Best Response 0 when didn't i?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
I was talking about the domain then.
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[D_{gof}=[1,1]\] \[Dfog=x \in (\infty,1]\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
you really tend to make things big when you misread, don;t you @ParthKohli
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
guys i think we can close the question i did not mean to create a big issue
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
it has been closed a long time ago @jonask
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
oh i dint notice,cos commentsn are still running
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.