## lgbasallote Group Title Find the domain: $h(x) = \sqrt{4-x} + \sqrt{x^2 - 1}$ one year ago one year ago

1. lgbasallote Group Title

i smell a race....

2. ParthKohli Group Title

Hint: you can't use positive numbers more than 4.

3. lgbasallote Group Title

^i wish you would have let me try first....

4. lgbasallote Group Title

5. lgbasallote Group Title

^and then you did it again @Jonask

sorry,like you said its a race

7. lgbasallote Group Title

i hate races.....

8. swissgirl Group Title

Ok just try to see when each square root is negative

9. lgbasallote Group Title

anyway....

10. lgbasallote Group Title

i suppose $$\sqrt{x^2 - 1}$$ will have no restrictions?

11. swissgirl Group Title

yes x=0

12. lgbasallote Group Title

hmm oh yeah

13. lgbasallote Group Title

didn't think of that

14. lgbasallote Group Title

then $$\sqrt{4-x}$$ would be 4 above?

15. swissgirl Group Title

I would say greater than 4

16. sauravshakya Group Title

@lgbasallote was that the question of 100 level???

17. lgbasallote Group Title

greater than 4...4 above...same shiz

18. Yahoo! Group Title

Take Seperately and Connect it by union (U)

19. lgbasallote Group Title

to be the best, one needs to master the basics @sauravshakya

$f(x)=x^2,g(x)=\sqrt{1-x}$ domain of$gof,fog$ domain

21. lgbasallote Group Title

^?

just a question that i wont interupt you can try

23. swissgirl Group Title

Domain is just 1 and 0

24. lgbasallote Group Title

g o f would be sqrt(1 - x^2) it would only be non-negative if 0 <= x <= 1

25. lgbasallote Group Title

so the domain is 0<=x<=1

26. swissgirl Group Title

for f(g(x))

27. lgbasallote Group Title

f o g would be 1- x so all real numbers

28. Yahoo! Group Title

$Domain=(-\infty,0) U (0,4]$

29. ParthKohli Group Title

0 isn't included in the domain since $$\sqrt{0^2 - 1} = \sqrt{-1}$$ and this is a real function.

30. Yahoo! Group Title

Lol...@ParthKohli u see it is a open Bracket.....

31. lgbasallote Group Title

"real" function?

32. ParthKohli Group Title

@Yahoo! I wasn't talking to you.

33. ParthKohli Group Title

Yeah, which has all ranges as real numbers.

34. Yahoo! Group Title

oh.....Sorry...) @ParthKohli

35. lgbasallote Group Title

now you confuse me...you're telling me they're wrong?

36. ParthKohli Group Title

swissgirl Best Response 1 Domain is just 1 and 0 that ^^

37. lgbasallote Group Title

hmm seems one of the answers here is wrong then...wonder which

38. ParthKohli Group Title

Okay, let me ask you a question. Why didn't you include all real numbers in the domain? @lgbasallote

39. lgbasallote Group Title

i did

40. lgbasallote Group Title

when didn't i?

41. ParthKohli Group Title

lgbasallote Best Response 0 i suppose sqrt(x62−1) will have no restrictions? swissgirl Best Response 1 yes x=0 lgbasallote Best Response 0 hmm oh yeah

42. ParthKohli Group Title

0 is included in all real numbers.

43. lgbasallote Group Title

since when was $$\sqrt{-1}$$ real @ParthKohli ?

44. ParthKohli Group Title

45. lgbasallote Group Title

....what exactly are you saying?

46. ParthKohli Group Title

ParthKohli 0 0 isn't included in the domain since sqrt(0^2 - 1) = sqrt(-1) and this is a real function. <argument happens> ParthKohli 0 Okay, let me ask you a question. Why didn't you include all real numbers in the domain? @lgbasallote lgbasallote Best Response 0 i did lgbasallote Best Response 0 when didn't i? <some more convo> lgbasallote Best Response 0 since when was √−1 real @ParthKohli ?

47. lgbasallote Group Title

48. ParthKohli Group Title

You are contradicting yourself. First, you say that you have included all real numbers in the domain. Then, by "since when was √−1 real @ParthKohli ?," you mean that 0 is not in the domain.

49. lgbasallote Group Title

by the way 1) none of us said 0 is included in the domain (we were talking about restrictions) 2) sqrt -1 is not a real function

$D_g=(-\infty,1),D_f=\mathbb{R}$ $fog=\left| 1-x \right|$$gof=\sqrt{1-x^2}$

51. lgbasallote Group Title

^?

52. ParthKohli Group Title

No, real function means that for all domains, the range will be real. We have to get a domain which keeps all ranges real.

53. lgbasallote Group Title

54. ParthKohli Group Title

That 0 is not in the domain.

55. lgbasallote Group Title

and isn't that what we said?

56. ParthKohli Group Title

You said that you included all real numbers in the domain. -.-

57. lgbasallote Group Title

when???

58. lgbasallote Group Title

59. ParthKohli Group Title

ParthKohli 0 Okay, let me ask you a question. Why didn't you include all real numbers in the domain? @lgbasallote lgbasallote i did 10 minutes ago lgbasallote Best Response 0 when didn't i?

60. ParthKohli Group Title

I was talking about the domain then.

$D_{gof}=[-1,1]$ $Dfog=x \in (-\infty,1]$

62. lgbasallote Group Title

you really tend to make things big when you misread, don;t you @ParthKohli

guys i think we can close the question i did not mean to create a big issue

64. lgbasallote Group Title

it has been closed a long time ago @jonask

oh i dint notice,cos commentsn are still running