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zaphod

  • 2 years ago

How do i differentiate this and find the gradient at point x=2

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  1. zaphod
    • 2 years ago
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    \[y = \frac{4}{3x-4}\]

  2. zaphod
    • 2 years ago
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    @Callisto @precal @SmoothMath

  3. zaphod
    • 2 years ago
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    @ParthKohli

  4. Jonask
    • 2 years ago
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    \[(\frac{ f }{ g })^ '=\frac{ f^'g-fg^' }{ g^2 }\]

  5. Jonask
    • 2 years ago
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    qutient rule

  6. Jonask
    • 2 years ago
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    \[f=4,g=3x-4\]

  7. zaphod
    • 2 years ago
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    i dont understnd

  8. Jonask
    • 2 years ago
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    \[f^'=0,g^'=3\] so just plug in

  9. zaphod
    • 2 years ago
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    @satellite73 @Pallavi06 @SmoothMath @experimentX

  10. Jonask
    • 2 years ago
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    \[\frac{ dy }{ dx }=\frac{ 0(3x-4) -3(4)}{ (3x-4)^2 }=\frac{ -12 }{ (3x-4)^2 }\]

  11. Jonask
    • 2 years ago
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    \[\frac{ -12 }{ (3(2)-4)^2 }=-3\]

  12. zaphod
    • 2 years ago
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    aren't there any easy methd?

  13. Pallavi06
    • 2 years ago
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    no........this is the method..........

  14. zaphod
    • 2 years ago
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    \[4(3x-4)^{-2}\] how do i do this now

  15. Pallavi06
    • 2 years ago
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    u have to differentiate it??

  16. zaphod
    • 2 years ago
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    yh

  17. zaphod
    • 2 years ago
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    wht is chain rule

  18. Jonask
    • 2 years ago
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    \[\frac{ dy }{ dx }=\frac{dz }{ dx }\frac{ dy }{ dz }\]

  19. Jonask
    • 2 years ago
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    \[\frac{ 4 }{ 3x-4 }=4(3x-4)^{-1}\] let\[z=3x-4\] \[\frac{dz}{dt}=3\] \[y=4z^{-1}\] \[\frac{ dy }{ dz}=-4z^{-2}\]

  20. Jonask
    • 2 years ago
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    \[\frac{ dy }{ dx }=?\]

  21. Jonask
    • 2 years ago
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    \[3(-4z^{-2})=-12(3x-4)^{-2}\]

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