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zaphod Group Title

How do i differentiate this and find the gradient at point x=2

  • 2 years ago
  • 2 years ago

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  1. zaphod Group Title
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    \[y = \frac{4}{3x-4}\]

    • 2 years ago
  2. zaphod Group Title
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    @Callisto @precal @SmoothMath

    • 2 years ago
  3. zaphod Group Title
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    @ParthKohli

    • 2 years ago
  4. Jonask Group Title
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    \[(\frac{ f }{ g })^ '=\frac{ f^'g-fg^' }{ g^2 }\]

    • 2 years ago
  5. Jonask Group Title
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    qutient rule

    • 2 years ago
  6. Jonask Group Title
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    \[f=4,g=3x-4\]

    • 2 years ago
  7. zaphod Group Title
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    i dont understnd

    • 2 years ago
  8. Jonask Group Title
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    \[f^'=0,g^'=3\] so just plug in

    • 2 years ago
  9. zaphod Group Title
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    @satellite73 @Pallavi06 @SmoothMath @experimentX

    • 2 years ago
  10. Jonask Group Title
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    \[\frac{ dy }{ dx }=\frac{ 0(3x-4) -3(4)}{ (3x-4)^2 }=\frac{ -12 }{ (3x-4)^2 }\]

    • 2 years ago
  11. Jonask Group Title
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    \[\frac{ -12 }{ (3(2)-4)^2 }=-3\]

    • 2 years ago
  12. zaphod Group Title
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    aren't there any easy methd?

    • 2 years ago
  13. Pallavi06 Group Title
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    no........this is the method..........

    • 2 years ago
  14. zaphod Group Title
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    \[4(3x-4)^{-2}\] how do i do this now

    • 2 years ago
  15. Pallavi06 Group Title
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    u have to differentiate it??

    • 2 years ago
  16. zaphod Group Title
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    yh

    • 2 years ago
  17. zaphod Group Title
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    wht is chain rule

    • 2 years ago
  18. Jonask Group Title
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    \[\frac{ dy }{ dx }=\frac{dz }{ dx }\frac{ dy }{ dz }\]

    • 2 years ago
  19. Jonask Group Title
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    \[\frac{ 4 }{ 3x-4 }=4(3x-4)^{-1}\] let\[z=3x-4\] \[\frac{dz}{dt}=3\] \[y=4z^{-1}\] \[\frac{ dy }{ dz}=-4z^{-2}\]

    • 2 years ago
  20. Jonask Group Title
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    \[\frac{ dy }{ dx }=?\]

    • 2 years ago
  21. Jonask Group Title
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    \[3(-4z^{-2})=-12(3x-4)^{-2}\]

    • 2 years ago
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is replying to Can someone tell me what button the professor is hitting...

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