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AEB047
Group Title
How do you do
3x+3y+z
5x+2y+2z=7
3x2y+3z=9
for x,y,z?
 one year ago
 one year ago
AEB047 Group Title
How do you do 3x+3y+z 5x+2y+2z=7 3x2y+3z=9 for x,y,z?
 one year ago
 one year ago

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AEB047 Group TitleBest ResponseYou've already chosen the best response.0
dw:1350857319350:dw
 one year ago

ShadowRatchet6 Group TitleBest ResponseYou've already chosen the best response.0
They are a system of equations. First, find the value of one of the variables, say, x, relative to another variable, like if I had \[y = 3x+4\] and \[y = 8x 3\] the first one would become \[x= \frac{ y4 }{ 3 }\] and then you substitue that x value into the second equation, making it \[y = 8(\frac{ y4 }{ 3 })  3\] Now you can solve for y. Similarly, these equations you also solve for x, y and z, but here, for the first equation, the equation doesn't equal anything. I think you should fix it.
 one year ago
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