A community for students.
Here's the question you clicked on:
 0 viewing
AEB047
 3 years ago
How do you do
3x+3y+z
5x+2y+2z=7
3x2y+3z=9
for x,y,z?
AEB047
 3 years ago
How do you do 3x+3y+z 5x+2y+2z=7 3x2y+3z=9 for x,y,z?

This Question is Closed

ShadowRatchet6
 3 years ago
Best ResponseYou've already chosen the best response.0They are a system of equations. First, find the value of one of the variables, say, x, relative to another variable, like if I had \[y = 3x+4\] and \[y = 8x 3\] the first one would become \[x= \frac{ y4 }{ 3 }\] and then you substitue that x value into the second equation, making it \[y = 8(\frac{ y4 }{ 3 })  3\] Now you can solve for y. Similarly, these equations you also solve for x, y and z, but here, for the first equation, the equation doesn't equal anything. I think you should fix it.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.