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AEB047 Group TitleBest ResponseYou've already chosen the best response.0
for what variable?
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
Is the equation \[\Large y = \frac{xv}{b}\] OR \[\Large y = x\frac{v}{b}\] ??
 2 years ago

Dani101 Group TitleBest ResponseYou've already chosen the best response.0
the first one
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
your first step is to multiply both sides by 'b'
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
what do you get when you do this?
 2 years ago

Dani101 Group TitleBest ResponseYou've already chosen the best response.0
But i thought you cant multiply a different variable with another
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
you can, there's no rule that says you can't
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
x times y is just xy (sure we can't find the numeric value of that, but we can just say it's xy)
 2 years ago

Dani101 Group TitleBest ResponseYou've already chosen the best response.0
Im confused, so like you multiply b by x and b by v?
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
you just multiply both sides by 'b' to get \[\Large y = \frac{xv}{b}\] \[\Large yb = xv\] what's next?
 2 years ago

Dani101 Group TitleBest ResponseYou've already chosen the best response.0
oh, um i really don't know, my teacher didn't really explain this to us. Don't you just leave the problem like that since you cant do anything else?
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
no, you can add 'v' to both sides and this completely isolates x
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
\[\Large yb = xv\] \[\Large yb+v = xv+v\] \[\Large yb+v = x\] \[\Large x = yb+v\]
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
and now you're done
 2 years ago

Dani101 Group TitleBest ResponseYou've already chosen the best response.0
Ohhhh, Thank you very much that was helpful
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
yw
 2 years ago
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