## 3psilon Help with math of this? Find T , 2T *sin45 = Mg one year ago one year ago

1. 3psilon

@Algebraic!

2. Algebraic!

wut?

3. Algebraic!

$T= \frac{ Mg }{ 2 \sin 45 }$

4. 3psilon

The answer says it = Mg/2 what happens to the root2 / 2

5. Algebraic!

no idea what you're asking... tbh

6. 3psilon

hahha Just wanna know how they got from $2T *\frac{ \sqrt{2} }{ 2 } = Mg$ to$T =$

7. 3psilon

mg/2

8. 3psilon

idk whats happening to the root 2 over 2

9. 3psilon

Yeah , but I don't see how they're getting rid of the square root?

10. Algebraic!

$\frac{ \sqrt{2}Mg }{ 2 }$

11. Algebraic!

right?

12. 3psilon

yes

13. Algebraic!

so, I guess you're asking:$\sqrt{2}T =Mg$ $T = \frac{Mg }{ \sqrt{2}}$ $T = \frac{Mg }{ \sqrt{2}} \frac{ \sqrt{2} }{ \sqrt{2} }$

14. 3psilon

But they got T = Mg/2 in the book that I'm using?

15. 3psilon

I guess it's just a typo

16. Algebraic!

possibly.

17. Algebraic!

maybe the answer is actually Mg/2 ... I don't know.

18. 3psilon

Hahah thanks I know the questions was very vague but thanks :)

19. Algebraic!

did you want me to look the actual problem?

20. 3psilon

I'll draw it, or attempt to

21. 3psilon

|dw:1350873308436:dw|

22. 3psilon

Find the tension in the two ropes

23. Algebraic!

ok..

24. Algebraic!

yep, you're right... should be sqrt(2) Mg /2