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Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.2\[T= \frac{ Mg }{ 2 \sin 45 }\]

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0The answer says it = Mg/2 what happens to the root2 / 2

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.2no idea what you're asking... tbh

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0hahha Just wanna know how they got from \[2T *\frac{ \sqrt{2} }{ 2 } = Mg \] to\[T = \]

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0idk whats happening to the root 2 over 2

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0Yeah , but I don't see how they're getting rid of the square root?

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.2\[\frac{ \sqrt{2}Mg }{ 2 }\]

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.2so, I guess you're asking:\[\sqrt{2}T =Mg\] \[T = \frac{Mg }{ \sqrt{2}}\] \[T = \frac{Mg }{ \sqrt{2}} \frac{ \sqrt{2} }{ \sqrt{2} }\]

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0But they got T = Mg/2 in the book that I'm using?

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0I guess it's just a typo

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.2maybe the answer is actually Mg/2 ... I don't know.

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0Hahah thanks I know the questions was very vague but thanks :)

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.2did you want me to look the actual problem?

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0I'll draw it, or attempt to

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0Find the tension in the two ropes

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.2yep, you're right... should be sqrt(2) Mg /2
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