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3psilon Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic!
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
\[T= \frac{ Mg }{ 2 \sin 45 }\]
 one year ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
The answer says it = Mg/2 what happens to the root2 / 2
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
no idea what you're asking... tbh
 one year ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
hahha Just wanna know how they got from \[2T *\frac{ \sqrt{2} }{ 2 } = Mg \] to\[T = \]
 one year ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
idk whats happening to the root 2 over 2
 one year ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
Yeah , but I don't see how they're getting rid of the square root?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
\[\frac{ \sqrt{2}Mg }{ 2 }\]
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
so, I guess you're asking:\[\sqrt{2}T =Mg\] \[T = \frac{Mg }{ \sqrt{2}}\] \[T = \frac{Mg }{ \sqrt{2}} \frac{ \sqrt{2} }{ \sqrt{2} }\]
 one year ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
But they got T = Mg/2 in the book that I'm using?
 one year ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
I guess it's just a typo
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
possibly.
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
maybe the answer is actually Mg/2 ... I don't know.
 one year ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
Hahah thanks I know the questions was very vague but thanks :)
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
did you want me to look the actual problem?
 one year ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
I'll draw it, or attempt to
 one year ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
dw:1350873308436:dw
 one year ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
Find the tension in the two ropes
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.2
yep, you're right... should be sqrt(2) Mg /2
 one year ago
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