3psilon
Help with math of this? Find T , 2T *sin45 = Mg



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3psilon
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@Algebraic!

Algebraic!
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wut?

Algebraic!
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\[T= \frac{ Mg }{ 2 \sin 45 }\]

3psilon
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The answer says it = Mg/2 what happens to the root2 / 2

Algebraic!
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no idea what you're asking... tbh

3psilon
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hahha Just wanna know how they got from \[2T *\frac{ \sqrt{2} }{ 2 } = Mg \]
to\[T = \]

3psilon
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mg/2

3psilon
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idk whats happening to the root 2 over 2

3psilon
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Yeah , but I don't see how they're getting rid of the square root?

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\[\frac{ \sqrt{2}Mg }{ 2 }\]

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right?

3psilon
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yes

Algebraic!
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so, I guess you're asking:\[\sqrt{2}T =Mg\]
\[T = \frac{Mg }{ \sqrt{2}}\]
\[T = \frac{Mg }{ \sqrt{2}} \frac{ \sqrt{2} }{ \sqrt{2} }\]

3psilon
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But they got T = Mg/2 in the book that I'm using?

3psilon
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I guess it's just a typo

Algebraic!
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possibly.

Algebraic!
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maybe the answer is actually Mg/2 ... I don't know.

3psilon
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Hahah thanks I know the questions was very vague but thanks :)

Algebraic!
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did you want me to look the actual problem?

3psilon
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I'll draw it, or attempt to

3psilon
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dw:1350873308436:dw

3psilon
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Find the tension in the two ropes

Algebraic!
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ok..

Algebraic!
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yep, you're right... should be sqrt(2) Mg /2