3psilon
  • 3psilon
Help with math of this? Find T , 2T *sin45 = Mg
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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3psilon
  • 3psilon
@Algebraic!
anonymous
  • anonymous
wut?
anonymous
  • anonymous
\[T= \frac{ Mg }{ 2 \sin 45 }\]

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3psilon
  • 3psilon
The answer says it = Mg/2 what happens to the root2 / 2
anonymous
  • anonymous
no idea what you're asking... tbh
3psilon
  • 3psilon
hahha Just wanna know how they got from \[2T *\frac{ \sqrt{2} }{ 2 } = Mg \] to\[T = \]
3psilon
  • 3psilon
mg/2
3psilon
  • 3psilon
idk whats happening to the root 2 over 2
3psilon
  • 3psilon
Yeah , but I don't see how they're getting rid of the square root?
anonymous
  • anonymous
\[\frac{ \sqrt{2}Mg }{ 2 }\]
anonymous
  • anonymous
right?
3psilon
  • 3psilon
yes
anonymous
  • anonymous
so, I guess you're asking:\[\sqrt{2}T =Mg\] \[T = \frac{Mg }{ \sqrt{2}}\] \[T = \frac{Mg }{ \sqrt{2}} \frac{ \sqrt{2} }{ \sqrt{2} }\]
3psilon
  • 3psilon
But they got T = Mg/2 in the book that I'm using?
3psilon
  • 3psilon
I guess it's just a typo
anonymous
  • anonymous
possibly.
anonymous
  • anonymous
maybe the answer is actually Mg/2 ... I don't know.
3psilon
  • 3psilon
Hahah thanks I know the questions was very vague but thanks :)
anonymous
  • anonymous
did you want me to look the actual problem?
3psilon
  • 3psilon
I'll draw it, or attempt to
3psilon
  • 3psilon
|dw:1350873308436:dw|
3psilon
  • 3psilon
Find the tension in the two ropes
anonymous
  • anonymous
ok..
anonymous
  • anonymous
yep, you're right... should be sqrt(2) Mg /2

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