anonymous
  • anonymous
This question is driving me crazy. I don't necessarily want all of the steps, just a push in the right direction. Thank-you. A natural gas mixture is burned in a furnace at a power-generating station at a rate of 13.0 mol per minute. (a) If the fuel consists of 9.3 mol CH4, 3.1 mol C2H6, 0.40 mol C3H8, and 0,20 mol C4H10, what mass of CO2(g) is produced per minute? (b) How much heat is released per minute? So what immediately struck me is that part (a) could be determined by normal stoichiometric methods, but the rate part is confusing me. Also I am not sure how to get the heat from
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Since the information is given as a rate (gas mixture burnt at 13.0 mol per minute) when you calculate the mass of CO2 the answer will also be a rate. For the heat you will either need to use bond enthalpies (from tables) and calculate that.
anonymous
  • anonymous
Ok, so bond enthalpies, not standard enthalpies of formation?
anonymous
  • anonymous
You can use standard enthalpies of formation as well. They should give you approximately the same answer.

Looking for something else?

Not the answer you are looking for? Search for more explanations.