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AdhaZeera Group TitleBest ResponseYou've already chosen the best response.0
dw:1350884315409:dw
 one year ago

AdhaZeera Group TitleBest ResponseYou've already chosen the best response.0
Fence SHED 4feet 5feet 8feet
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1350884748553:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
ops i dident see the fence
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
Can he go inside the shed? And is he/she connected by a chain that is connected to the corner of the shed?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1350884878590:dw
 one year ago

AdhaZeera Group TitleBest ResponseYou've already chosen the best response.0
No he's not connected. I'm not sure. That's all my teacher wrote
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
he has to be connected by a chain to the shed right?
 one year ago

AdhaZeera Group TitleBest ResponseYou've already chosen the best response.0
Wait... yes..
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1350885122452:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1350885496696:dw
 one year ago

AdhaZeera Group TitleBest ResponseYou've already chosen the best response.0
How do I calculate it?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
break the shape in to smaller shapes
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
Unkle Rhaukus I like your drawings, but what is the actual value?
 one year ago

AdhaZeera Group TitleBest ResponseYou've already chosen the best response.0
81 sq ft??
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
I'm very sure I know how to do it. Just give me some time to work it out.
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
its not easy, but i'm still working.
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
Ok, here it comes. Writing it up. :) !!!!!
 one year ago

AdhaZeera Group TitleBest ResponseYou've already chosen the best response.0
You there?
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
yeah hang on almost done
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
you might be surprised but i got it.
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
GOT IT!!!!
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
im not sure why you had to integrate
 one year ago

AdhaZeera Group TitleBest ResponseYou've already chosen the best response.0
Thank you!
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
we know the are of a circle is πr^2, so a semicircle has area (πr^2)/2 and a quater circle has area (πr^2)/4
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
I integrated because I wanted to take the whole circle and then subtract the parts where the goat can't go. The area of the top of the circle is curved and the goat can't go there. So I created a function and integrated it so that I could find that exact area that is fenced off.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1350888457508:dw
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
@ AdhaZeera Do you understand what I did when I integrated. I will explain it to you if you want. I used calculus to arrive at that answer.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1350888515709:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
the sector is 1/12 of a circle
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
@ UnkleRhaukus I know that there is a formula that is A= (theta)r^2/2 but I don't how it works here.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[A=\frac{\pi\times 3^2}4+\frac{\pi \times8^2}{2}+\frac{\pi \times8^2}{12}+\frac{4\times 8}{2}\]\[=\pi\times\frac{465}{12}+16\]\[\approx 140\]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
well theta was 30° right? angles of segment / angle in circle \[30°/360°=1/12\] area of segment / area of circle \[\frac{\pi r^2}{12}\qquad/\qquad\pi r^2\]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
i had to use a trig ratio to to get 30° btw
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
Your value comes to 140.35 mine is 141.7, its off only by a hair and is a very good approximation, but mine is exact.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
where did i error?
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
not sure, but its pretty darn good.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[A=\frac{\pi\times 3^2}4+\frac{\pi \times8^2}{2}+\frac{\pi \times8^2}{12}+\frac{4\times 8}{2}=\pi\times\frac{475}{12}+16\approx140.35\]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
@Fellowroot i think we got different answers because we were solving different regions our pictures are different
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.2
dw:1350891993500:dw The only thing I don't know if that if the 5 feet fence touches the edge of the circle or if there is a gab. For the solution i provided it doesn't matter though. On my pic, the 'x', I really don't know that distance, it may make a difference for your answer, i don't know.
 one year ago