Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

AdhaZeera Group Title

What area can the goat roam?

  • one year ago
  • one year ago

  • This Question is Closed
  1. AdhaZeera Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350884315409:dw|

    • one year ago
  2. AdhaZeera Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Fence SHED 4feet 5feet 8feet

    • one year ago
  3. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350884748553:dw|

    • one year ago
  4. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ops i dident see the fence

    • one year ago
  5. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Can he go inside the shed? And is he/she connected by a chain that is connected to the corner of the shed?

    • one year ago
  6. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350884878590:dw|

    • one year ago
  7. AdhaZeera Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    No he's not connected. I'm not sure. That's all my teacher wrote

    • one year ago
  8. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    he has to be connected by a chain to the shed right?

    • one year ago
  9. AdhaZeera Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Wait... yes..

    • one year ago
  10. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350885122452:dw|

    • one year ago
  11. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350885496696:dw|

    • one year ago
  12. AdhaZeera Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    How do I calculate it?

    • one year ago
  13. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    break the shape in to smaller shapes

    • one year ago
  14. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Unkle Rhaukus I like your drawings, but what is the actual value?

    • one year ago
  15. AdhaZeera Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    81 sq ft??

    • one year ago
  16. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    I'm very sure I know how to do it. Just give me some time to work it out.

    • one year ago
  17. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    its not easy, but i'm still working.

    • one year ago
  18. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Ok, here it comes. Writing it up. :) !!!!!

    • one year ago
  19. AdhaZeera Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    You there?

    • one year ago
  20. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    yeah hang on almost done

    • one year ago
  21. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    you might be surprised but i got it.

    • one year ago
  22. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    GOT IT!!!!

    • one year ago
  23. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    im not sure why you had to integrate

    • one year ago
  24. AdhaZeera Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank you!

    • one year ago
  25. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    we know the are of a circle is πr^2, so a semicircle has area (πr^2)/2 and a quater circle has area (πr^2)/4

    • one year ago
  26. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    I integrated because I wanted to take the whole circle and then subtract the parts where the goat can't go. The area of the top of the circle is curved and the goat can't go there. So I created a function and integrated it so that I could find that exact area that is fenced off.

    • one year ago
  27. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350888457508:dw|

    • one year ago
  28. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    @ AdhaZeera Do you understand what I did when I integrated. I will explain it to you if you want. I used calculus to arrive at that answer.

    • one year ago
  29. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350888515709:dw|

    • one year ago
  30. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    the sector is 1/12 of a circle

    • one year ago
  31. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    @ UnkleRhaukus I know that there is a formula that is A= (theta)r^2/2 but I don't how it works here.

    • one year ago
  32. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[A=\frac{\pi\times 3^2}4+\frac{\pi \times8^2}{2}+\frac{\pi \times8^2}{12}+\frac{4\times 8}{2}\]\[=\pi\times\frac{465}{12}+16\]\[\approx 140\]

    • one year ago
  33. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    well theta was 30° right? angles of segment / angle in circle \[30°/360°=1/12\] area of segment / area of circle \[\frac{\pi r^2}{12}\qquad/\qquad\pi r^2\]

    • one year ago
  34. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i had to use a trig ratio to to get 30° btw

    • one year ago
  35. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Your value comes to 140.35 mine is 141.7, its off only by a hair and is a very good approximation, but mine is exact.

    • one year ago
  36. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    where did i error?

    • one year ago
  37. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    not sure, but its pretty darn good.

    • one year ago
  38. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[A=\frac{\pi\times 3^2}4+\frac{\pi \times8^2}{2}+\frac{\pi \times8^2}{12}+\frac{4\times 8}{2}=\pi\times\frac{475}{12}+16\approx140.35\]

    • one year ago
  39. UnkleRhaukus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @Fellowroot i think we got different answers because we were solving different regions our pictures are different

    • one year ago
  40. Fellowroot Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1350891993500:dw| The only thing I don't know if that if the 5 feet fence touches the edge of the circle or if there is a gab. For the solution i provided it doesn't matter though. On my pic, the 'x', I really don't know that distance, it may make a difference for your answer, i don't know.

    • one year ago