anonymous
  • anonymous
HIYA! Can anyone explain to me how to solve this? PLEASE AND THANK YA! :) 7) A 200 kg polar bear is sliding down a water slide accelerating at 4 m/s2. a. What is the Fnet acting on the polar bear? b. What is the Fg,x acting on the polar bear? c. What Ff is acting on the polar bear?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amriju
  • amriju
f net=4*200=800n.....whats Fg,x..?
anonymous
  • anonymous
gravity in the x direction
amriju
  • amriju
force of gravity in x direction...?...0 ofcrse.... and force of friction....will be 200*(g-4) do check the answers

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anonymous
  • anonymous
yay! youre really good at this! :)
amriju
  • amriju
thnks....but did u get it...?
anonymous
  • anonymous
it doesnt tell me if its the correct answer or not but when i solved it, i got the same answers!
anonymous
  • anonymous
im just a little iffy about fgx but i think its just 0
amriju
  • amriju
hey...remember vectors...? a vector can't have a resolved part in a direction perpendicular to it....?...its jst dat...g acts in y direction...it cant have a part of it in x direction..meaning perp dircn...so accn=0...force=0...sorry for late reply...an idiot called me...
anonymous
  • anonymous
loll nahh its okay! hahah oh yeah!! dudee. you should just take my test for me :P lol
amriju
  • amriju
lol.....u solving which book...?
anonymous
  • anonymous
what do u mean? lol
amriju
  • amriju
these probs...from where r they..?
anonymous
  • anonymous
test review
anonymous
  • anonymous
a worksheet my teacher gave us
amriju
  • amriju
k.......u live in the US...?.
anonymous
  • anonymous
yess ma'am!
amriju
  • amriju
well....i am not accualy a ma'am...i jst happen to disguise my name in my profile username...i am a boy..lolllllll
anonymous
  • anonymous
ohh! hahaha! sorrry my badd
amriju
  • amriju
anyways continue studing...i wud be happy to help u in case of any probs....
anonymous
  • anonymous
okay thanks!

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