sedighn
What would be the resistance of a piece of
aluminium wire 1.8 mm in diameter and 10 m long?(The resistivity of aluminium is 2.8 × 10–8 Ω m.)



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imron07
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\[R=\rho L/A\]

sedighn
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Yes so for A I did...
π * ((0.9)^3)^2 and got 5.91 m^2

sedighn
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Is that correct? :o

imron07
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if you mean \(A=\pi\times(0.9\times10^{3})^2\), you're correct.

sedighn
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Oops now I realise why I've got the wrong answer... I forgot to add in the x10 bit :P Thank you

imron07
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:)