aussy123
A = {(x, y): y >x2}
help me graph
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UnkleRhaukus
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can you graph y=x^2
aussy123
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No
UnkleRhaukus
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ok lets make a table
aussy123
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okay
UnkleRhaukus
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lets have x for -3 to 3
|dw:1350917238347:dw|
UnkleRhaukus
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if y=x^2
when x= -3
y= (-3)^2=
aussy123
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9
UnkleRhaukus
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good , so
UnkleRhaukus
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|dw:1350917333290:dw|
aussy123
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So you go down the table and make the equation
y= x^2
UnkleRhaukus
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can you fill in the rest of the table?
aussy123
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okay
aussy123
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|dw:1350917528971:dw|
UnkleRhaukus
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|dw:1350917500305:dw|
UnkleRhaukus
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good work, can you polt the rest of the points?
aussy123
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yes
aussy123
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|dw:1350917698467:dw|
UnkleRhaukus
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very good,
now if we connect these points, then the line will be y=x^2
UnkleRhaukus
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but the question is y>x^2
aussy123
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but where would we shade
UnkleRhaukus
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well if y is greater then x^2,
the y values in the the shaded region must be of greater values than the y=x^2 curve
UnkleRhaukus
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so shade the region above the curve
aussy123
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Okay thanks, I think I have it now!!
UnkleRhaukus
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some times it is good to choose a point and check it ,
say the point (0,1)
which is above the curve,
to check
y>x^2
1>0^2
1>0
which is true, so the point is in the region
aussy123
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ok thanks for clarifying that, I will use this method on the other questions!!
UnkleRhaukus
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the last thing to mention is that the line in not included in the region because we are doing y>x^2
if we were doing y≥x^2, the line would be included
aussy123
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Because of the greater than or equal sign????
UnkleRhaukus
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so maybe draw a dashed line like this |dw:1350918432085:dw|
aussy123
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okay is it possible to shade in more than one place?
UnkleRhaukus
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yes
UnkleRhaukus
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but you would need a complicated equation
aussy123
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okay then