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Edutopia

  • 3 years ago

F(x) = 1/(x^2-4), such that F''(x) = (6x^2-8)/(x^2-4)^3 I am asked to find the intervals of concavity and possible points of inflection. But....

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  1. Edutopia
    • 3 years ago
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    When i set F''(x)=0 then i get a value (+-2/sqrt(3)) and WOLF says that this graph has no points of inflection (because it is asymptotic). What am i misunderstanding?

  2. NoelGreco
    • 3 years ago
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    The minus sign in the numerator of F'' should be a plus sign. That makes the numerator always >0.

  3. calculusfunctions
    • 3 years ago
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    Let me know if you're on line at he same time I am and I'll explain.

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