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Edutopia
F(x) = 1/(x^2-4), such that F''(x) = (6x^2-8)/(x^2-4)^3 I am asked to find the intervals of concavity and possible points of inflection. But....
When i set F''(x)=0 then i get a value (+-2/sqrt(3)) and WOLF says that this graph has no points of inflection (because it is asymptotic). What am i misunderstanding?
The minus sign in the numerator of F'' should be a plus sign. That makes the numerator always >0.
Let me know if you're on line at he same time I am and I'll explain.